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jeyben [28]
3 years ago
11

Which of the following would require the largest volume of 0.100 M sodium hydroxide solution for neutralization?:

Chemistry
1 answer:
bazaltina [42]3 years ago
8 0

Answer:10.0 mL of 0.00500 M phosphoric acid

Explanation:

If we look at the Ka values of the acids, we will realize that phosphoric acid has a Ka of 7.1 * 10-3. It is the only acid in the list having acid dissociation constant less than 1. This means that it does not ionize easily in solution and a very large volume of base must be added to ensure that it reacts completely. Acids with Ka >1 are generally regarded as strong acids. All the acids listed have Ka>1 except phosphoric acid.

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7 0
2 years ago
In an experiment, the same mass of magnesium metal reacted with the same amount of two different acids. the acid used in reactio
denpristay [2]

The mole ratio of the reaction shows that equal volumes of hydrogen gas will be produced by the two reactions.

<h3>What is the mole ratio of a reaction?</h3>

The mole ratio of a reaction is the ratio in which the reactants and products of a given reaction occur for the reaction to proceed to completion.

The mole ratio of a reaction is also known as the stoichiometry of the reaction.

The equation of the two reactions are given below:

Mg + 2HCl \rightarrow MgCl_2 + H_2

Mg + 2CH_3COOH \rightarrow (CH_3COO)_2Mg + H_2 \\

From the equation of the reaction reaction, an equal volume of hydrogen gas will be produced by the two reactions.

Therefore, the mole ratio of the reaction shows that equal volumes of hydrogen gas will be produced by the two reactions.

Learn more about mole ratio at: brainly.com/question/19099163

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6 0
1 year ago
If I have 340 mL of a 1.5 M NaBr solution, what will the concentration be if I add 560 mL more water to it?
ipn [44]

Answer:

0.5667 M ≅ 0.57 M.

Explanation:

It is known that the no. of millimoles of a solution before dilution is equal to the no. of millimoles of the solution after the dilution.

It can be expressed as:

(MV) before dilution = (MV) after dilution.

M before dilution = 1.5 M, V before dilution = 340 mL.

M after dilution = ??? M, V after dilution = 340 mL + 560 mL = 900 mL.

∴ M after dilution = (MV) before dilution/(V) after dilution = (1.5 M)(340 mL)/(900 mL) = 0.5667 M ≅ 0.57 M.

5 0
2 years ago
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Rzqust [24]
The answer is protons.
8 0
2 years ago
the most common source of copper (Cu) is the mineral chalcopyrite (CuFeS2). How many kilograms of chalcopyrite must be mined to
lara [203]
<span>0.650 kg... I think, 
But what are the answer choices?</span>
3 0
3 years ago
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