All categories

3 years ago

What is the formula of a radius circle ?

Mathematics

2 answers:

UkoKoshka [18]3 years ago

5 0

I assume you happen to mean, what is the formula for a circle.

The formula is:

A= $\pi r^{2}$

Bas_tet [7]3 years ago

3 0

r= C/2 x 3.14 would be the answer to this

You might be interested in

Fractions equivalent to 1:2 Please don’t be bots that post it in a link

stepan [7]

Answer:

1/2 or .5 or 1:2

Step-by-step explanation:

3 0

3 years ago

4a - 3b + 2c - 2a - 3b + 4c. please show work

sveticcg [70]

All I can see is adding all the like terms. If thats whats its asking its 2a-6b+6c.

8 0

3 years ago

A 10 foot ladder is leaning against a wall. Call x the distance from the top of the ladder to the ground, and call y the distanc

liq [111]

$-5.3\:\text{ft/s}$

Step-by-step explanation:

We start by applying the Pythagorean theorem to the ladder, with its length L as the hypotenuse:

$L^2 = 100\:\text{ft}^2 = x^2 + y^2$

where x is the vertical distance from the top of the ladder to the ground and y is the horizontal distance from the bottom of the ladder to the wall. Taking the derivative of the above expression with respect to time, we get

$0 = 2x\dfrac{dx}{dt} + 2y\dfrac{dy}{dt}$

Solving for dx/dt, we get

$\dfrac{dx}{dt} = -\left(\dfrac{y}{x}\right)\dfrac{dy}{dt} = -\left(\dfrac{\sqrt{L^2 - x^2}}{x}\right)\dfrac{dy}{dt}$

We know that

$\dfrac{dy}{dt} = 4\:\text{ft/s}$

when x = 6 ft. So the rate at which the top of the ladder is going down is

$\dfrac{dx}{dt} = -\left(\dfrac{\sqrt{100\:\text{ft}^2 - (6\:\text{ft})^2}}{6\:\text{ft}}\right)(4\:\text{ft/s})$

$\:\:\:\:\:\:\:= -5.3\:\text{ft/s}$

The negative sign means that the distance x is decreasing as y is increasing.

5 0

3 years ago

HELPPP PLSSSS FOR EXTRA POINS AND BRAINLEST I NEED

Alik [6]

Answer:

Answer is C

Step-by-step explanation:

It is not in a stright line or in a line at all!

Hope this helped!!!

6 0

3 years ago

Read 2 more answers

Graph the system of inequalities presented here then use your graph to answer the following questions:

Nookie1986 [14]

Answer:

Part A) The graph in the attached figure (see the explanation)

Part B) The ordered pair is a solution of the system of inequalities (is included in the solution area for the system)

Step-by-step explanation:

Part 1) Graph the system of inequalities

we have

$y> 5x+5$ ----> inequality A

The solution of the inequality A is the shaded area above the dashed line $y=5x+5$

The slope pf the dashed line A is positive m=5

The y-intercept of the dashed line A is (0,5)

The x-intercept of the dashed line A is (-1,0)

$y>-\frac{1}{2}x+1$ ----> inequality B

The solution of the inequality B is the shaded area above the dashed line $y=-\frac{1}{2}x+1$

The slope pf the dashed line B is negative m=-1/2

The y-intercept of the dashed line B is (0,1)

The x-intercept of the dashed line B is (2,0)

The solution of the system of inequalities is the shaded area above the dashed line A and above the dashed line B

using a graphing tool

see the attached figure

Part B) Is the point (-2, 5) included in the solution area for the system? Justify your answer mathematically

we know that

If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities

substitute the value of x and the value of y in each inequality

For x=-2, y=5

Verify inequality A

$5>5(-2)+5$

$5>-5$ ---> is true

The ordered pair satisfy inequality A

Verify inequality B

$5>-\frac{1}{2}(-2)+1$

$5>2$ ---> is true

The ordered pair satisfy inequality B

therefore

The ordered pair is a solution of the system of inequalities (is included in the solution area for the system)

6 0

3 years ago