Answer:
Width=13cm
Length=18cm
Step-by-step explanation:
Width of the Initial Photograph=9cm
Length of the Initial Photograph=14cm
If width and length are increased by an equal amount, say x
New Width=9+x
New Length=14+x
Area of the new photo is 108 square centimeters greater than the area of the original photo.
Area of Original Photo=14*9=126cm²
Aeea of the New Photo=126+108=234cm²
Therefore:
(9+x)(14+x)=234
126+9x+14x+x²-234=0
x²+23x-108=0
x²+27x-4x-108=0
x(x+27)-4(x+27)=0
(x+27)(x-4)=0
x+27=0 or x-4=0
x=-27 or x=4
Since x≠-27
x=4cm
The dimensions of the new photo are:
Width=9+x=9+4=13cm
Length=14+x=14+4=18cm
The answer in a fraction format is 2/9 or decimal format will be 0.222222222
Answer:
12 °F
2°F per hour
Step-by-step explanation:
The difference can be found by substracting:
7°F-( -5 °F)
=12 °F
To find the average change in temperature per hour, divide by how many hours between 6 to midnight. Between 6 to midnight is 6 hours.
12°F / 6 hours
= 2°F/ hour
-2x=-4 or x=2
2x =-4 or x=-2
Answer:
The time a student learns mathematics is important for their score
Step-by-step explanation:
Observe the boxes diagrams. Where the horizontal axis represents the score obtained by the students in the test.
The vertical lines that divide the boxes in two represent the value of the median.
The median is the value that divides 50% of the data.
For the class of the morning the value of the median is 50 points, with a maximum value of 80 and a minimum value of 10.
For the afternoon class, the median value is 65 points with a minimum value of 30 and a maximum value of 100.
This indicates that in general, the highest number of high scores were obtained in the afternoon class.
Therefore it can be said that the time a student learns mathematics is important for their score
