What is the "scientific method"?

A car is being tested on a track. The driver approaches the test section at a speed of 28 m s−1. He then accelerates at a unifor

dedylja [7]

The uniform acceleration of the car is 4.485 m/s².

<h3>Acceleration of the car</h3>

The uniform acceleration of the car is calculated as follows;

v² = u² + 2as

a = (v² - u²)/2s

where;

v is final velocity = 41 m/s
u is initial velocity = 28 m/s
s is distance = 100 m
a is acceleration = ?

a = (41² - 28²)/(2 x 100)

a = 4.485 m/s²

Thus, the uniform acceleration of the car is 4.485 m/s².

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7 0

2 years ago

Resultant Displacement. I WILL GIVE BRAINLIEST!!!!

aleksley [76]

Answer:

displacement will be 83km from the marker that reads 249km.

8 0

3 years ago

A spring has a relaxed length of 35 cm (0.35 m) and its spring stiffness is 12 N/m. You glue a 66 gram block (0.066 kg) to the t

Sonbull [250]

We have that the value for y is

$y=0.12376m$

From the Question we are told that

Relaxed length of 35 cm (0.35 m)

Spring stiffness is 12 N/m.

Glue a 66 gram block (0.066 kg)

Total length is l_t=16 cm

Block during a 0.24-second interval

Generally the equation for the Force of spring of block is mathematically given as

$F_{spring}=kx\\\\\ F_{spring}=12*(0.35-0.16)\\\\ F_{spring}=2.28N$

Generally

$F_{elastic}=-mg\\\\F_{elastic}=-0.066*9.8\\\\F_{elastic}=-0.6468N$

Generally,Net Force

$F_{net}=F_{spring}-F_{elastic}\\\\F_{net}=2.28N-(-0.6468N)\\\\F_{net}=2.9268N$

Generally,Velocity of block

$V_y=\frac{py}{m}$

Where

$Py= F_{net}*dt\\\\Py= 2.9268*0.08\\\\Py=0.234144$

Therefore

$V_y=\frac{0.234144}{0.066}\\\\V_y=3.547m/s$

Generally the equation for the Velocity of block is mathematically given as

$Vy=\frac{yf-yt}{t-t_0}\\\\y=(3.547(0.08-0))-0.16$

$y=0.12376m$

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4 0

3 years ago

You are standing 30 m from a window that is 30 m off the ground. Your friend tries to toss you something, but only throws it str

pochemuha

Answer:

minimum initial velocity is 21.35 m/s

Explanation:

given data

distance S = 30 m

height h = 30 m

maximum acceleration a = 2 m/s²

to find out

minimum initial velocity that your friend could have thrown the object to enable you to catch

solution

first we get here time with the help of second equation of motion

time = $\sqrt{\frac{2h}{a} }$ ..................1

put her value we get

time = $\sqrt{\frac{2*30}{2} }$

time = 5.477 second

and that is time which tossed object must be take so we apply here again second equation of motion that is

-S = ut - 0.5 × gt² .......................2

-30 = u× 5.477 - 0.5 ×9.8×5.477²

solve it we get

u = 21.35 m/s

so minimum initial velocity is 21.35 m/s

3 0

3 years ago

Read 2 more answers

3. What is the potential energy of a 8 Newton book sitting on a shelf that is 12 meters high?

Svetradugi [14.3K]

Answer:

P = 96 J

Explanation:

Given that,

Weight of the book, W = mg = 8 N

It is placed at a height of 12 m

We need to find the potential energy of the book. The potential energy of an object is given by the formula as follows :

E = mgh

mg = Weight

$E=8\ N\times 12\ m\\E=96\ J$

So, the potential energy of the book is 96 J.

8 0

4 years ago