Planck find the correct curve for the specturm of light emitted by a hot object by vibrational energies of the atomic resonators were quantized.
<h3>Briefing :</h3>
- The energy density of a black body between λ and λ + dλ is the energy E=hc/λ of a mode times the density of states for photons, times the probability that the mode is occupied.
- This is Planck's renowned equation for a black body's energy density.
- According to this, electromagnetic radiation from heated bodies emits in discrete energy units or quanta, the size of which depends on a fundamental physical constant (Planck's constant). The basis of infrared imaging is the correlation between spectral emissivity, temperature, and radiant energy, which is made possible by Planck's equation.
Learn more about the Planck's constant with the help of the given link:
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Answer:
14.4 L
Explanation:
Initially, the gas is at stp (standard conditions), which means
and its initial volume is
Later, the gas is heated to a final temperature of
and the pressure is increased to
So we can use the ideal gas equation to find the new volume, V2:
Answer:
Explanation:
Let assume that gases inside bulbs behave as an ideal gas and have the same temperature. Then, conditions of gases before and after valve opened are now modelled:
Bulb A (2 L, 2 atm) - Before opening:
Bulb B (3 L, 4 atm) - Before opening:
Bulbs A & B (5 L) - After opening:
After some algebraic manipulation, a formula for final pressure is derived:
And final pressure is obtained:
Answer:
Q = 7837500 Joules.
Explanation:
<u>Cho các dữ liệu sau đây;</u>
Khối lượng = 25 kg
Nhiệt độ ban đầu = 25°C
Nhiệt độ cuối cùng = 100°C
Nhiệt dung riêng = 4,18 * 10³ = 4180 J/kg.K
Để tìm nhiệt lượng cần thiết;
Về mặt toán học, nhiệt dung được cho bởi công thức;
Ở đâu;
- Q là nhiệt dung hoặc nhiệt lượng.
- m đại diện cho khối lượng của một vật.
- c biểu diễn nhiệt dung riêng của nước.
- dt thể hiện sự thay đổi của nhiệt độ.
<u>Chuyển đổi:</u>
Nhiệt độ ban đầu = 25°C đến Kelvin = 273 + 25 = 298 K
Nhiệt độ cuối cùng = 100°C đến Kelvin = 273 + 100 = 373 K
dt = T2 - T1
dt = 373 - 298
dt = 75 Kelvin
Thay các giá trị vào phương trình, ta có;
Q = 7837500 Joules.