Explanation:
Given that,
A student travels 11 m north and then turns around to travel 25 m south.
Total time, t = 12 s
The total distance or the total path covered by the student is equal to 11 m + 25 m = 36 m
Displacement of the student or the shortest path covered is d = 25-11 = 14 m
(a) The student's average speed = total distance/total time

(b) The student's average velocity = total displacement/total time

Answer:
The mass of unknown object is 8.62Kg
Explanation:
To develop this problem it is necessary to apply the equations related to the Drag force and the Force of Gravity.
For the given point, that is, the moment at which the terminal velocity is reached, the two forces equalize, that is,

By definition we know that the Drag force is defined as

Where,
Drag coefficient
Density
A =Cross-sectional Area
V = Velocity
In the other hand we have,

Where,
Mass of sphere
Mass of unknown object
Equating the two equations we have to

Re-arrange for m_2,

Our values are given by,






Replacing in the equation we have,


<em>Therefore the mass of unknown object is 8.62Kg</em>
The correct answer is the Golden Gate Bridge
3.Es tarde y mi taxi no llega. Estoy ____.
(5 Points)
preocupada
contenta
<span>anything harder than mohs scale 7 so eg Topaz, Corundum and diamond representing mohs scale 8 9 and 10 respectively.</span>