Answer:
1964.8 J
1150 Joules
Explanation:
m = Mass of bullet = 0.5 kg
= Change in temperature = (327-20)
c = Specific heat of lead = 128 J/kg °C
=
= Latent heat of fusion of lead =
(Values taken from properties of lead table)
Heat is given by
The heat needed to raise the bullet to its final temperature is 1964.8 J
Change in volume is given by
The volume of the bullet when it comes to rest is
Heat needed for melting
The additional heat needed to melt the bullet is 1150 Joules
Answer:
a) Pi = 3200 w
b) Pe = 640 w
Explanation:
Solar radiation is 800 w/m²
a) Area of solar panel is 4 m²
Then Power Incident is:
Pi = Solar radiation x Area of solar panel array , then
Pi = 800 w/m² * 4 m²
Pi = 3200 w or Pi = 3.2 Kw
b) Solar panels efficiency is 20%
Electricity production: Pe
Pe = Pi * η where η is efficiency η = 20 % η = 0,2
Pe = 3200 w * 0,2
Pe = 640 w or Pe = 0,640 Kw
Answer:
i wanna say tranverse if not surface
Explanation:
Answer:
Explanation:
Gravitational potential energy is the energy an object possesses due to its position. It is calculated using the following formula:
Where <em>m</em> is the mass, <em>g</em> is the acceleration due to gravity, and <em>h</em> is the height.
The object has a mass of 8.72 kilograms. Assuming this occurs on Earth, the acceleration due to gravity is 9.8 meters per second squared. The object gains 446 Joules of potential energy.
Let's convert the units of Joules. This makes the process of canceling units simpler later on. 1 Joule is equal to 1 kilogram meter squared per second squared. The object gains 446 J, which is equal to 446 kg *m²/s².
- EP= 446 kg*m²/s²
- m= 8.72 kg
- g= 9.8 m/s²
Substitute the values into the formula.
Multiply on the right side of the equation.
We are solving for the height, so we must isolate the variable h. It is being multiplied by 85.456 kg*m/s². The inverse operation of multiplication is division, so we divide both sides by this value.
The units of kg*m/s² cancel, leaving meters as our unit.
The original measurements of mass and potential energy have 3 significant figures, so our answer must have the same.
For the number we calculated, that is the hundredths place. The 9 in the thousandths place to the right tells us to round the 1 up to a 2.
The object was lifted to a height of approximately <u>5.22 meters.</u>
Answer:
Voltage across 33 ohm resistor is 33.886 volt
Explanation:
We have given that there is RL circuit which contain two resistance and inductance
Resistance of two resistor
So equivalent resistance
Inductance of inductive reactance
So equivalent inductive reactance
Now equivalent impedance
Voltage is given as
So current
So voltage across 33 ohm resistor