Answer:
x₂=0.44m
Explanation:
First, we calculate the length the spring is stretch when the first block is hung from it:
Now, since the stretched spring is in equilibrium, we have that the spring restoring force must be equal to the weight of the block:
Solving for the spring constant k, we get:
Next, we use the same relationship, but for the second block, to find the value of the stretched length:
Finally, we sum this to the unstretched length to obtain the length of the spring:
In words, the length of the spring when the second block is hung from it, is 0.44m.
There are two torques t1 and t2 on the beam due to the weights, one torque t3 due to the weight of the beam, and one torque t4 due to the string.
You need to figure out t4 to know the tension in the string.
Since the whole thing is not moving t1 + t2 + t3 = t4.
torque t = r * F * sinФ = distance from axis of rotation * force * sin (∡ between r and F)
t1 =3.2 * 44g
t2 = 7 * 49g
t3 = 3.5 * 24g
t4 = t1 + t2 + t3 = 5570,118
The t4 also is given by:
t4 = r * T * sin Ф
r = 7
Ф = 32°
T: tension in the string
T = t4 / (r * sinФ)
T = t4 / (7 * sin(32°))
T = 1501,6 N
your question doesnt make sense
B. a sound wave that he could just barely hear
<span>The correct answer is letter B. less than the angle of refraction. </span>When a beam of light passes at an oblique angle into a material of lower optical density, the angle of incidence is <span>less than the angle of refraction. The reason for that because the beam of light passes through an oblique angle.</span>
