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astra-53 [7]
4 years ago
11

The preview of the scientific method

Physics
1 answer:
galben [10]4 years ago
4 0

Answer:

the preview of the scientific method

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Human centrifuges are used to train military pilots and astronauts in preparation for high-g maneuvers. A trained, fit person we
jeka57 [31]

(a) 4.14 rad/s^2

The relationship beween centripetal acceleration and angular speed is

a=\omega^2 r

where

\omega is the angular speed

r is the radius of the circular path

Here we gave

a = 9g = 88.2 m/s^2 is the centripetal acceleration

r = 5.15 m is the radius

Solving for \omega, we find:

\omega = \sqrt{\frac{a}{r}}=\sqrt{\frac{88.2 m/s^2}{5.15 m}}=4.14 rad/s^2

(b) 21.3 m/s

The relationship between the linear speed and the angular speed is

v=\omega r

where

v is the linear speed

\omega is the angular speed

r is the radius of the circular path

In this problem we have

\omega=4.14 rad/s

r = 5.15 m

Solving the equation for v, we find

v=(4.14 rad/s)(5.15 m)=21.3 m/s

7 0
3 years ago
Read 2 more answers
If an object has no acceleration, can you conclude that no forces are exerted on it
MrMuchimi

No. It has no acceleration, which just means that the forces acting on it are equal and opposite, not that there are no forces exerted on it.

But if you're talking about the resulting Net Force, then yes you can conclude there is no Net Force acting on an object with no acceleration.

3 0
3 years ago
There is a 50 g sample of Ra-229. It has a half-life of 4 minutes.
Sloan [31]

Via half-life equation we have:


A_{final}=A_{initial}(\frac{1}{2})^{\frac{t}{h} }


Where the initial amount is 50 grams, half-life is 4 minutes, and time elapsed is 12 minutes.  By plugging those values in we get:

A_{final}=50(\frac{1}{2})^\frac{12}{4}=50(\frac{1}{2})^{3}=50(\frac{1}{8})=6.25g


There is 6.25 grams left of Ra-229 after 12 minutes.

4 0
4 years ago
Astronaut Jill leaves Earth in a spaceship and is now traveling at a speed of 0.280c relative to an observer on Earth. When Jill
Slav-nsk [51]

(B) 1.00 m

Explanation:

Since the meter stick is traveling with Jill, it will have the same speed as she does so relative to Jill, the meter stick is stationary so its length remains 1.00 m as measured by her.

8 0
3 years ago
You slide a slab of dielectric between the plates of a parallel-plate capacitor. As you do this, the potential difference betwee
LUCKY_DIMON [66]

Answer:

In this scenario adding the dielectric material in between the plates will have no effect on the capacitance of the plates since the voltage remains unchanged

Explanation:

Normally Introducing a dielectric into a capacitor decreases the electric field, which decreases the voltage, which increases the capacitance.

A capacitor with a dielectric stores the same charge as one without a dielectric, but at a lower voltage.

Voltage and capacitance are inversely proportional when charge is constant.

Now in this case the voltage remains the same hence the charges remain the same also because voltage is inversely proportional to capacitance

3 0
4 years ago
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