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3 years ago

Which statement best describes gamma radiation?

1 answer:

5 0

The correct answer is option 3. The gamma radiation has no mass and no charge. This is produced from the release of pure energy from the nucleus. This is simply a stream of high frequency energy.

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Liquid hexane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 4.3 g of hexane is mi

Ilya [14]

Answer:

We can produce 6.20 grams of CO2

Explanation:

Step 1: Data given

Mass of hexane = 4.3 grams

Molar mass of hexane = 86.18 g/mol

Mass of oxygen = 7.14 grams

Molar mass of oxygen = 32.0 g/mol

Step 2: The balanced equation

2C6H14 + 19O2 → 12CO2 + 14H2O

Step 3: Calculate moles

Moles = mass / molar mass

Moles hexane = 4.3 grams / 86.18 g/mol

Moles hexane = 0.0499 moles

Moles oxygen = 7.14 grams / 32.0 g/mol

Moles oxygen = 0.2231 moles

Step 4: Calculate the limiting reactant

For 2 moles hexane we need 19 moles O2 to produce 12 moles CO2 and 14 moles H2O

Oxygen is the limiting reactant. It will completely be consumed ( 0.2231 moles). Hexane is in excess. There will react 2/19 * 0.2231 = 0.02348 moles

There will be porduced 12/19 * 0.2231 = 0.1409 moles CO2

Step 5: Calculate mass CO2

Mass CO2 = moles CO2 * molar mass CO2

Mass CO2 = 0.1409 moles * 44.01 g/mol

Mass CO2 = 6.20 grams

We can produce 6.20 grams of CO2

5 0

3 years ago

Calculate the volume of liquid in the round flask sketched below. give your answer in liters, and round to the nearest 0.01l .

vovangra [49]

Hey There!

Assuming the part of the round flask containing liquid to be perfect sphere, we can calculate it's volume.

Given diameter of sphere = 24 cm

Therefore radius of the sphere, r= 24/2= 12 cm

Volume of the sphere of diameter 24 cm = (4/3)*pi*r³ = 7,238.23 cm3

Conversion of cm³ to L

1 L= 1 dm³

1 dm = 10 cm

Therefore 1L= 1 dm³ = 1000 cm³

So the volume of liquid in the round flask = 7.24 L( round of to nearest 0.01 L)

4 0

3 years ago

Draw the lewis structure for the polyatomic trisulfide s−23 anion. be sure to include all resonance structures that satisfy the

mezya [45]

The following are the steps involved in drawing Lewis structure of the polyatomic trisulfide anion $S_{3}^{2-}$ :

Total number of valence electrons = $(3 * 6) + 2 = 20 electrons$

Resonance is not possible in this ion. The molecular geometry of the ion will be bent as there are two lone pairs and two bond pairs on the central atom.

3 0

3 years ago

How many moles are in 3.45 g of Na2O?Round your answer to three significant

Neporo4naja [7]

Answer: There are 0.056 moles present in 3.45 g of $Na_{2}O$ .

Explanation:

Given : Mass = 3.45 g

Moles is the mass of substance divided by its molar mass.

Hence, moles of $Na_{2}O$ (molar mass = 61.98 g/mol) is as follows.

$Moles = \frac{mass}{molar mass}\\= \frac{3.45 g}{61.98 g/mol}\\= 0.056 mol$

Thus, we can conclude that there are 0.056 moles present in 3.45 g of $Na_{2}O$ .

6 0

3 years ago

The combustion of methane(CH4) produces carbon dioxide and water. Assume that 2.0 mol of CH4 burned in the presence of excess ai

harkovskaia [24]

Answer:

The answer to your question is 98.9 %

Explanation:

Data

moles of methane = CH₄ = 2.0

excess air

Percent yield = ?

mass of CO₂ = 87 g

- Balanced chemical reaction

CH₄ + 2O₂ ⇒ CO₂ + 2H₂O

Reactants Elements Products

1 C 1

4 H 2

4 O 2

- Calculate the molar mass of CH₄

CH₄ = 12 + 4 = 16 g

- Convert the moles to mass

16 g of CH₄ ----------------- 1 mol

x ----------------- 2 moles

x = (2 x 16) / 1

x = 32 g of CH₄

-Calculate the theoretical formation of CO₂

16 g of CH₄ ----------------- 44 g of CO₂

32 g of CH₄ ---------------- x

x = (32 x 44) / 16

x = 88 g of CO₂

-Calculate the Percent yield

Percent yield = Actual yield/Theoretical yield x 100

Percent yield = 87/88 x 100

Percent yield = 98.9 %

3 0

3 years ago