Answer:
0.2943 Nm
Explanation:
Work done is given a the product of force and diatance moved and expressed by the formula
W=Fd
Here W represent work, F is applied force and d is perpendicular distance
Also, we know that F=mg where m is the mass of an object and g is acceleration due to gravity. Substituting this back into the initial equation then
W=mgd
Taking acceleration due to gravity as 9.81 m/s2 and substituting mass with 0.1 kg and distance with 0.3 m then
W=0.1*9.81*0.3=0.2943 Nm
With the use of electric force formula, the direction and magnitude of the net force exerted on the point charge q3 are 9.9 x
N and 66 degrees
ELECTRIC FORCE (F)
F = 
Where K = 9 x
N
/
The distance between
and
can be calculated by using Pythagoras theorem.
d = 
d = 46.7 cm = 0.467 m
For force
, substitute all the parameters into the formula above
= (9 x
x 3 x 1)/
= 2.7 x
/0.218
= 1.24 x
N
For force
, substitute all the parameters into the formula above
= (9 x
x 3 x 4)/
= 1.08 x
/0.1089
= 9.92 x
N
For force
, substitute all the parameters into the formula above
= (9 x
x 3 x 2)/
= 5.4 x
/0.1089
= 4.96 x
N
Summation of forces on Y component will be
=
-
Sin 45
= 9.92 x
- 1.24 x
Sin 45
= 9.04 x
N
Summation of forces on X component will be
=
-
Cos 45
= 4.96 x
- 1.24 x
Sin 45
= 4.08 x
N
Net Force = 
Net force = 
Net force = 9.9 x
N
The direction will be
Tan ∅ =
/
Tan ∅ = 9.04 x
/ 4.08 x 
Tan ∅ = 2.216
∅ =
(2.216)
∅ = 65.7 degrees
Therefore, the direction and magnitude of the net force exerted on the point charge q3 are 9.9 x
N and 66 degrees approximately.
Learn more about electric Force here: brainly.com/question/4053816
You use the equation Velocity = Acceleration X Time. 4x4=16m/s.
The car travels 18m in 3 seconds.
Answer:
Total distance traveled = 9 m
Explanation:
Given:
Distance travel towards north = 3 meter
Distance travel towards south = 6 meter
Find:
Total distance traveled
Computation:
Total distance traveled = Sum of total distance
Total distance traveled = Distance travel towards north + Distance travel towards south
Total distance traveled = 3 m + 6 m
Total distance traveled = 9 m