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Brrunno [24]
3 years ago
10

What length of tube would be required to produce a second tone under the same experimental conditions? Explain your answer.

Physics
1 answer:
Alisiya [41]3 years ago
7 0

There is an indirect relationship between length and frequency. The longer the length the pipe has, the higher frequency it is. The shorter the length the pipe has, the lower frequency it is.

<u>Explanation:</u>

The four properties of the string that affect its frequency are length, diameter, tension, and density. These properties are described below: When the length of a string is changed, it will vibrate with a different frequency. Shorter strings have higher frequency and therefore higher pitch.

The longer the tube is the lower the pitch of the note that it can emit. When a tube is heated it expands and so is longer! As the gas in the tube gets warmer the molecules move faster, that means they can carry the vibrations of the sound wave more rapidly and so the pitch goes up.

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A 265 g mass attached to a horizontal spring oscillates at a frequency of 3.40 Hz . At t =0s, the mass is at x= 6.20 cm and has
lara [203]

Answer:

The phase constant is 7.25 degree  

Explanation:

given data

mass = 265 g

frequency = 3.40 Hz

time t = 0 s

x = 6.20 cm

vx = - 35.0 cm/s

solution

as phase constant is express as

y = A cosФ ..............1

here A is amplitude that is = \sqrt{(\frac{v_x}{\omega })^2+y^2 }  = \sqrt{(\frac{35}{2\times \pi  \times y})^2+6.2^2 }  =  6.25 cm

put value in equation 1

6.20 = 6.25 cosФ

cosФ  = 0.992

Ф = 7.25 degree  

so the phase constant is 7.25 degree  

5 0
3 years ago
How much tension must a rope withstand if used to accelerate a 960-kg car from rest horizontally along a frictionless surface to
Svetach [21]
Use a=(dv/dt)         (change in velocity/ change in time)=acceleration
(1.2/5)=acceleration

F=ma (Newton's second law, Force= Mass x Acceleration

=960 x 0.24     F=230.4N If  T<230.4N then the tow rope will hold

7 0
3 years ago
an aircraft landing on an air craft carrier is brought to a complete stop from an inital velocity of 215km/hr in 2.7 seconds. wh
worty [1.4K]

u= 215 km/hr = 215 * 1000/ 3600 = aprx 60m/s
v=0
t=2.7sec
v= u - at
u= at
60/2.7 = 22.23 m/s^2



Hope it helps
8 0
2 years ago
A person weighing 600 Newtons gets on an elevator. The elevator lifts the person 6 meters in 10 seconds. How much power was used
Svetlanka [38]

Answer:

The power used is 360 Watts.

Explanation:

4 0
2 years ago
When you drop a 4.5 kg watermelon off the Dennison building, it reaches a terminal velocity of around 35 m/s second before smash
mart [117]

Answer:

3) 52500N

Explanation:

We use the mathematical definition of impulse as follows;

Ft = mv............(1)

were F is the force experienced, t is the time of impact, m is the mass of the object and v is the velocity of impact.

Given; m = 4.5kg, v = 35m/s, t = 3 milliseconds

however, 3milliseconds=3*10^{-3}s

From equation (1);

F=\frac{mv}{t}.............(2).

Substituting all necessary values into equation (2), we obtain the following;

F=\frac{4.5*35}{3*10^{-3}}}\\\\F= \frac{157.5.5}{0.003}\\\\F=52500N

6 0
3 years ago
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