Answer:
public class Class {
private String name ="";
private int score = 0;
//Method SetName
public void setName(String newName){
name = newName;
}
//Method SetScore
public void setScore(int newScore){
score = newScore;
}
//Method GetName
public String getName() {
return name;
}
//Method GetScore
public int getScore() {
return score;
}
}
Explanation:
- The class called Class is implemented in Java programming language
- It has two fields (instance variables name and score)
- Methods for setting the values of variables (mutator methods) or setters
- Methods for getting the values of the variables (accessor methods) getters
A bluetooth device in park/hold mode is part of the piconet but is in a low-power state. These are power saving modes of operation for Bluetooth devices which are connected to a piconet and are used when no data is to be transmitted.The hold mode is used when connecting several piconets or managing a low-power device such as temperature sensor. When the park mode is used t<span>he device is still synchronized to the piconet but does not participate in traffic.</span>
Answer:
Explanation:
#include<iostream>
#include<ctime>
#include<bits/stdc++.h>
using namespace std;
double calculate(double arr[], int l)
{
double avg=0.0;
int x;
for(x=0;x<l;x++)
{
avg+=arr[x];
}
avg/=l;
return avg;
}
int biggest(int arr[], int n)
{
int x,idx,big=-1;
for(x=0;x<n;x++)
{
if(arr[x]>big)
{
big=arr[x];
idx=x;
}
}
return idx;
}
int main()
{
vector<pair<int,double> >result;
cout<<"Enter 1 for iteration\nEnter 2 for exit\n";
int choice;
cin>>choice;
while(choice!=2)
{
int n,m;
cout<<"Enter N"<<endl;
cin>>n;
cout<<"Enter M"<<endl;
cin>>m;
int c=m;
double running_time[c];
while(c>0)
{
int arr[n];
int x;
for(x=0;x<n;x++)
{
arr[x] = rand();
}
clock_t start = clock();
int pos = biggest(arr,n);
clock_t t_end = clock();
c--;
running_time[c] = 1000.0*(t_end-start)/CLOCKS_PER_SEC;
}
double avg_running_time = calculate(running_time,m);
result.push_back(make_pair(n,avg_running_time));
cout<<"Enter 1 for iteration\nEnter 2 for exit\n";
cin>>choice;
}
for(int x=0;x<result.size();x++)
{
cout<<result[x].first<<" "<<result[x].second<<endl;
}
}
Answer:
Your solution is ready.
Explanation:
Visit: gotit-pro.com/design-a-gui-interface-to-accept-user-input-and-add-the-data-to-a-cell-phone
And get the complete working code for this assignment.
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Answer:
ArrayList a contains [2, 3, 3, 3, 4, 5, 3, 2, 1]
Explanation:
Given
The removeValue method
Required
The content of ArrayList a, after the method is called
From the question, we understand that arraylist a is:
![a= [2, 3, 4, 3, 3, 4, 4, 5, 4, 3, 2, 1]](https://tex.z-dn.net/?f=a%3D%20%5B2%2C%203%2C%204%2C%203%2C%203%2C%204%2C%204%2C%205%2C%204%2C%203%2C%202%2C%201%5D)
The function fails when the value to be removed appear consecutively in the list.
4 appears in index 5 and 6 of the list. Only one of the 4's will be removed
So, the updated list will be: [2, 3, 3, 3, 4, 5, 3, 2, 1]
