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IRINA_888 [86]
3 years ago
14

What are the three types of nuclear radiation

Chemistry
2 answers:
Nina [5.8K]3 years ago
8 0
Alpha,Beta and the Gamma
mixer [17]3 years ago
3 0

its actually, alpha particles, beta particles, and gamma rays


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#1: Which of the following is an exothermic reaction?
aleksandrvk [35]
<span>An exothermic reaction is one in which heat is released from the reagents into the ambient environment. Perhaps somewhat counterintuitively, condensation is in fact an example of such a reaction. During the process of the gas-to-liquid phase change, water goes from a higher-energy to lower-energy state of matter, and, as such, releases heat into the environment.</span>
5 0
3 years ago
Someone plz help me
a_sh-v [17]

Answer:

A experimental investigation

3 0
2 years ago
How many grams of KCl 03 are needed to produce 6.75 Liters of O2 gas measured at 1.3 atm pressure and 298 K?
Nina [5.8K]

11.48-gram of KCl0_3 are needed to produce 6.75 Liters of O_2  gas measured at 1.3 atm pressure and 298 K

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

First, calculate the moles of the gas using the gas law,

PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= 1.3 atm

V= 6.75 Liters

n=?

R= 0.082057338 \;L \;atm \;K^{-1}mol^{-1}

T=298 K

Putting value in the given equation:

\frac{PV}{RT}=n

n= \frac{1.3 \;atm\; X \;6.75 \;L}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X 298}

Moles = 0.3588 moles

Now,

Moles = \frac{mass}{molar \;mass}

0.3588 moles = \frac{mass}{32}

Mass= 11.48 gram

Hence, 11.48-gram of KCl0_3 are needed to produce 6.75 Liters of O_2 gas measured at 1.3 atm pressure and 298 K

Learn more about the ideal gas here:

brainly.com/question/27691721

#SPJ1

3 0
2 years ago
For each molecule of glucose processed during glycolysis, the net yield is ____.
olga nikolaevna [1]
(Starch) I hope this helps you please check again i'am not sure of my answer
3 0
3 years ago
DUPLICATE
Svet_ta [14]
As in relative abundance , one is take reference
So,
One is taken as 1:
Other is subtracted from it:
(1 - 0.6011)(atomic mass of Ga-71) 

Equation can be written as:
<span>69.723 = (0.6011)(68.9256) + (1-0.6011)x </span>
<span>(1-0.6011) is the percentage abundance of Ga-71 expressed in percentage: </span>

<span>Solving for x </span>
<span>28.2918 = 0.3989 x </span>
<span>x= 70.9246.......</span>
7 0
3 years ago
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