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erastova [34]
3 years ago
12

What ion do most basic compounds contain? A. H2O B. H2O- C. OH- D. H-

Chemistry
1 answer:
mel-nik [20]3 years ago
4 0
C is the correct answer I think
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What was the half-life of a new isotope?
REY [17]
The half-life of any substance is the amount of time taken for half of the original quantity of the substance present to decay. The half-life of a radioactive substance is characteristic to itself, and it may be millions of years long or it may be just a few seconds.

In order to determine the half-life of a substance, we simply use:
t(1/2) = ln(2) / λ

Where λ is the decay constant for that specific isotope.
8 0
3 years ago
How many liters of ammonia gas can be formed from 54.1 liters of hydrogen
Aleks04 [339]
 <span>The reaction is N2 + 3H2 -> 2NH3 
So the amount of NH3 formed is 2/3 of the amount of H2 = 2/3 * 13.7 = 9.13 Liters.</span><span>The answer is 9.13

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5 0
3 years ago
The reaction of a quantity of sulfur trioxide with water gives an acid with a volume of 2 l, containing 1.8 mol of the dissolved
777dan777 [17]

Answer :]

A.)Calculate the mass of ammonium sulfate that would be obtained by reacting with ammonia acid.

<em>Correct me if i'm wrong :]</em>

8 0
2 years ago
How is the concentration of h3o ions and oh- ions different in an acid solution and a basic soulution?
Lubov Fominskaja [6]
In an acidic solution, the concentration of H+ is greater than the concentration of OH-. The pH will be less than 7.
In a basic solution, the concentration of OH- is greater than the concentration of H+. The pH will be greater than 7.
In a neutral solution, the concentration of H+ ions to OH-ions will be equal, and will therefore have a pH of 7. (This is due to water autoionization, which we usually ignore because it is small in other circumstances.)
5 0
3 years ago
"A solution with a total volume of 850.0 mL contains 43.5 g Mg(NO3)2. If you remove 25.0 mL of this solution and then dilute thi
ycow [4]

Answer: C = 0.014M

Explanation:

From n= m/M= CV

m =43.5 M= 148, V=850ml

43.5/148= C× 0.85

C= 0.35M

Applying dilution formula

C1V1=C2V2

C1= 0.35, V1= 25ml, C2=?, V2= 600ml

0.35× 25 = C2× 600

C2= 0.014M

7 0
3 years ago
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