How many moles of nitrogen gas (N) are needed to react with 7.5 moles of hydrogen (H)?
1 answer:
You might be interested in
Answer: " 13.5 g Al " ;
→ that is: "13.5 grams of aluminum."
<u>____________________________</u>
Explanation:
<u>____________________________</u>
<u>Note</u>: What is missing from the question is the "balanced chemical equation" for the "chemical reaction" that contains:
The reactants: "aluminum (Al) " ; and "chlorine (Cl) " ; and:
The product: "aluminum choloride (AlCl₃) " .
____________________________
The "balanced chemical equation" is:
____________________________
2 Al + 3 Cl₂ → 2 AlCl₃ ;
_____________________________
<u>Note</u>: The molecular weight of "aluminum (Al)" is: " 26.98 g /mol " .
____________________________
So: We call solve using a technique known as: "dimensional analysis" :
____________________________
0.500 mol AlCl₃ *
____________________________
<u>Note</u>: The units of "mol AlCl₃" cancel out to "1' ; and:
The units of "mol Al" cancel out to "1" ; and we are left with:
____________________________
" g Al ["grams of aluminum"] ;
____________________________
<u>Note</u>: We can "cancel out the "2's" ; since "2/2 = 1 " ; and we have:
→ (0.500 * 26.98) g Al ;
= 13.49 g Al ;
→ Round to 3 (Three) significant figures;
→ Since: "0.500" has 3 (Three) significant figures:
____________________________
= 13.5 g Al ; that is: "13.5 grams of aluminum."
____________________________
Hope this is helpful!
Best wishes to you in your academic pursuits—and within the "Brainly" community!
____________________________