Answer:
1.67mol/L
Explanation:
Data obtained from the question include:
Mole of solute (K2CO3) = 5.51 moles
Volume of solution = 3.30 L
Molarity =?
Molarity is simply the mole of solute per unit litre of the solution. It can be expressed mathematically as:
Molarity = mole of solute /Volume of solution
Molarity = 5.51 mol/3.30 L
Molarity = 1.67mol/L
Therefore, the molarity of K2CO3 is 1.67mol/L
Calcium Flouride. It's an ionic bond. Cation + anion with the suffix -ide
Formula for density is mass / volume.
100 ml is volume. 76.5g of cooking oil is
the mass.
Therefore
76.5/100 = .765g/ml