All categories

3 years ago

What is a semiconductor

Chemistry

2 answers:

natka813 [3]3 years ago

7 0

Answer:

Explanation:

I hope God it has to be 20 characters so here but I hope this right please have a god day

Law Incorporation [45]3 years ago

6 0

Answer:

The answer is "B. A conductor that has less conductivity than do metallic conductors."

Explanation:

I took the quiz on A P E X, and I got it right.

You might be interested in

You have a 0.7 M solution. Your job is to produce 50 mL of a 0.4 M solution.

Andreyy89

Answer: A. 28.6 ml of the 0.7 M solution we need to start with.

B. There are 0.02 moles of solute were in the 0.7 M solution.

C. Amount of water to be added is 21.4 ml

D. The resulting solution will have concentration of 0.28 M

Explanation:

According to the dilution law,

$M_1V_1=M_2V_2$

where,

$M_1$ = molarity of stock solution = 0.7 M

$V_1$ = volume of stock solution = ?

$M_1$ = molarity of diluted solution = 0.4 M

$V_1$ = volume of diluted solution = 50 ml

Putting in the values we get:

$0.7\times V_1=0.4\times 50$

$V_1=28.6ml$

A. 28.6 ml of the 0.7 M solution we need to start with.

B. Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

$Molarity=\frac{n\times 1000}{V_s}$

where,

n = moles of solute

$V_s$ = volume of solution in ml

$0.7=\frac{n\times 1000}{28.6}$

$n=0.02$

Thus there are 0.02 moles of solute were in the 0.7 M solution.

C. Amount of water to be added = (50-28.6 ) ml = 21.4 ml

D. If water added is $2\times 21.4=42.8 ml$

$0.7\times 28.6=M_2\times 71.4$

$M_2=0.28M$

If volume of concentrated solution will be more , the resulting solution will have lesser concentration of 0.28 M

8 0

3 years ago

several of the flame tests were shades of red. what should be done in the laboratory to correctly identify one of these ions

yuradex [85]

You have to do another test to record the differences.

6 0

3 years ago

The temperature of a sample of water from the faucet increases from 22.7°C to 48.9°C when 3,710J are applied through electric sh

MakcuM [25]

Answer:

33.8.

Explanation:

Hello,

In this case, since the used equation is:

$Q=mCp(T_2-T_1)$

Whereas the specific heat is 4.184 J/(g°C), we compute the mass as follows:

$m=\frac{Q}{Cp(T_2-T_1)}$

Thus, the mass turns out:

$m=\frac{3,710J}{4.184\frac{J}{g\°C} (48.9-22.7)\°C}\\\\m=33.8g$

And without units:

33.8.

Best regards.

8 0

3 years ago

Magnesium metal (0.100 mol) and a volume of aqueous hydrochloric acid that contains 0.500 mol of HCl are combined and react to c

jok3333 [9.3K]

Answer:

2.24 L of hydrogen gas, measured at STP, are produced.

Explanation:

Given, Moles of magnesium metal, $Mg$ = 0.100 mol

Moles of hydrochloric acid, $HCl$ = 0.500 mol

According to the reaction shown below:-

$Mg_{(s)} + 2HCl_{(aq)}\rightarrow MgCl_2_{(aq)} + H_2_{(g)}$

1 mole of Mg reacts with 2 moles of $HCl$

0.100 mol of Mg reacts with 2*0.100 mol of $HCl$

Moles of $HCl$ must react = 0.200 mol

Available moles of $HCl$ = 0.500 moles

Limiting reagent is the one which is present in small amount. Thus, $Mg$ is limiting reagent.

The formation of the product is governed by the limiting reagent. So,

1 mole of $Mg$ on reaction forms 1 mole of $H_2$

0.100 mole of $Mg$ on reaction forms 0.100 mole of $H_2$

Mole of $H_2$ = 0.100 mol

At STP,

Pressure = 1 atm

Temperature = 273.15 K

Volume = ?

Using ideal gas equation as:

$PV=nRT$

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

1 atm × V L = 0.100 × 0.0821 L.atm/K.mol × 273.15 K

2.24 L of hydrogen gas, measured at STP, are produced.

4 0

3 years ago

A base

hichkok12 [17]

B, turns red litmus paper to blue

5 0

3 years ago

What is a semiconductor￼

What is a semiconductor