AgNO₃ + NaCl = NaNO₃<span> + AgCl
1 mol AgNO</span>₃ --------------- 1 mole AgCl
15 mol AgNO₃ ------------- ? mole AgCl
moles AgCl = 15 x 1 / 1
moles AgCl = 15 / 1
<span>= </span>15 moles AgCl
<span>hope this helps!</span>
Answer:
New volume V2 = 92.7 Liter (Approx)
Explanation:
Given:
V1 = 106 l
T1 = 45 + 273.15 = 318.15 K
P1 = 740 mm
T2 = 20 + 273.15 = 293.15 K
P2 = 780 mm
Find:
New volume V2
Computation:
P1V1 / T1 = P2V2 / T2
(740)(106) / (318.15) = (780)(V2) / (293.15)
New volume V2 = 92.7 Liter (Approx)