Assuming an ebullioscopic constant of 0.512 °C/m for the water, If you add 30.0g of salt to 3.75kg of water, the boiling-point elevation will be 0.140 °C and the boiling-point of the solution will be 100.14 °C.
<h3>What is the boiling-point elevation?</h3>
Boiling-point elevation describes the phenomenon that the boiling point of a liquid will be higher when another compound is added, meaning that a solution has a higher boiling point than a pure solvent.
- Step 1: Calculate the molality of the solution.
We will use the definition of molality.
b = mass solute / molar mass solute × kg solvent
b = 30.0 g / (58.44 g/mol) × 3.75 kg = 0.137 m
- Step 2: Calculate the boiling-point elevation.
We will use the following expression.
ΔT = Kb × m × i
ΔT = 0.512 °C/m × 0.137 m × 2 = 0.140 °C
where
- ΔT is the boiling-point elevation
- Kb is the ebullioscopic constant.
- b is the molality.
- i is the Van't Hoff factor (i = 2 for NaCl).
The normal boiling-point for water is 100 °C. The boiling-point of the solution will be:
100 °C + 0.140 °C = 100.14 °C
Assuming an ebullioscopic constant of 0.512 °C/m for the water, If you add 30.0g of salt to 3.75kg of water, the boiling-point elevation will be 0.140 °C and the boiling-point of the solution will be 100.14 °C.
Learn more about boiling-point elevation here: brainly.com/question/4206205
Answer:
The most important ore of aluminum is<u> Bauxite.</u>
And its chemical formula is
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Explanation:
Bauxite is the most important ore of Aluminium from which Aluminium is extracted. Bauxite is a rock and composed of Aluminium bearing mineral.
And its chemical formula is
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It contains Gibbsite, Bohmite and Diaspore along with iron.
It is a soft material with somewhat white to grey to reddish brown in colour.
It has an earthy lustre and low specific gravity.
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The answer would be periods 6-7 :)
Answer:
n = 2
Explanation:
We will solve this problem using the Rydberg equation since all the information is given. One has to be very careful in solving for the energy level becuse the numbers are slightly messy as is solving for n.
When the energy of the transition is given in wavelength it is best to use the Rydberg equation in the form:
1/Lambda = Rh x Z² x ( 1/ n₁² - 1/ n₂²)
Lambda= 30.4 x 10 ⁻⁹ m ( 1nm = 1 x 10⁻⁹ m)
Rh = 10973700 m⁻¹
Z = 4 for Be³⁺
1/(30.4 x 10⁻⁹ )= 10973700 x (16) x (1/ n² - 1/4²)=
0.1873 + 1/16 = 1/ n²
n² = 1/ 0.25
n ² = 4
n= √4 = 2
D is the answer blah blah blah