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katrin2010 [14]
3 years ago
6

A glass marble is rubbed against a piece of silk. As a result the piece of fabric acquires extra electrons. What happens to the

glass marble?
Chemistry
2 answers:
Montano1993 [528]3 years ago
7 0

Answer:

This is an electrostatic attraction. Since the fabric silk has acquired negative charges (electrons), the marble would have lost the same number of electrons  to become positively charged.

Hence, there will be electrostatic force of attraction.

Natalija [7]3 years ago
4 0

Answer:

There was an electron transfer where the marble has lost the same amount of electrons (being positively charged) that the piece of silk has gained (being negatively charged).

Explanation:

As a result of this transfer of electrons and the charges induced in the objects they will attract.

When a body is endowed with electrical properties, that is, it acquires electrical charges, it is said to have been electrified.

Electrification is one of the phenomena that studies electrostatics.

To explain how static electricity originates, we must consider that matter is made of atoms, and atoms of charged particles, a nucleus surrounded by a cloud of electrons. Normally, matter is neutral (not electrified), it has the same number of positive and negative charges.

Some atoms are easier to lose their electrons than others. If a material tends to lose some of its electrons when it comes into contact with another, it is said to be more positive in the Triboelectric series. If a material tends to capture electrons when it comes into contact with another material, that material is more negative in the triboelectric series.

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The exhaust gas from an automobile contains 1.5 percent by volume of carbon monoxide. What is the concentration of CO in mg/m' a
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Explanation:

The concentration of CO in mg/m3 can be calculated as

C (mg/m3) =(P/RT)*MW*C_{ppm}

For standard conditions (1 atm and 25°C), P/RT is 0.0409.

Concentration of 1.5% percent by volume of CO is equivalent to 1.5*10,000 ppm= 15,000 ppm CO.

The molecular weigth of CO is 28 g/mol.

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C=(P/RT)*MW*C_{ppm}\\\\C=0.0409*28*15,000=17,178

(b) For 200°C and 1.1 atm,

P/RT=0.0409*(P/P_{std})*(T_{std}/T)\\P/RT=0.0409*(1.1atm/1atm)*(273+15K/273+200K)=0.0277

Then the concentration in mg/m3 is

C=(P/RT)*MW*C_{ppm}\\\\C=0.0277*28*15,000=11,625

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