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3 years ago

What is the significance of an electronegativity difference of 1.7 between 2 atoms?

Chemistry

2 answers:

stealth61 [152]3 years ago

8 0

Explanation:

Electronegativity is defined as the ability of an atom to attract electrons towards itself.

Whereas when there is difference in values electronegativity of two different atoms then it is known as electronegativity difference.

For example, in a HCl compound the hydrogen atom is electropositive and chlorine atom is electronegative. Electronegativity value of hydrogen is 2.1 and chlorine has 3.0.

Hence, difference in their electronegativities is 3.0 - 2.1 = 0.9.

Also, it is known that when the electronegativity difference is less than or equal to 1.7 then the bond formed between the combining atoms will be polar covalent.

natta225 [31]3 years ago

7 0

It represents the boundary between what is considered to be ionic or a covalent bond.

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prisoha [69]

What’s the weather like in the other states?

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3 years ago

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A sample of oxygen occupies 20.1 liters under a pressure of 1520 torr at 25.0o What volume would it occupy at 25.0oC if the pres

Zolol [24]

Answer:

The volume that the sample of oxygen would occupy at 25 ° C if the pressure were reduced to 760.0 torr is 40.2 L

Explanation:

Boyle's law establishes the relationship between the pressure and the volume of a gas when the temperature is constant, so that the pressure of a gas in a closed container is inversely proportional to the volume of the container. That is, if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases.

Boyle's law is expressed mathematically as:

Pressure * Volume = constant

or P * V = k

Considering an initial state 1 and a final state 2, it is true:

P1* V1= P2*V2

In this case:

P1= 20.1 L
V1= 1520 torr
P2= 760 torr
V2= ?

Replacing:

20.1 L* 1520 torr= 760 torr* V2

Solving:

$V2=\frac{20.1 L* 1520 torr}{760 torr}$

V2= 40.2 L

The volume that the sample of oxygen would occupy at 25 ° C if the pressure were reduced to 760.0 torr is 40.2 L

4 0

3 years ago

Many portable gas heaters and grills use propane, C3H8(g). Using enthalpies of formation, calculate the quantity of heat produce

Elodia [21]

Answer: 600 kJ

Explanation:

C₃H₈ (g) + 5 O₂ (g) =============== 3 CO₂ (g) + 4 H₂O (l)

Δ⁰Hf kJ/mol -104 0 -393.5 -285.8

Δ⁰Hcomb C₃H₈ = 3(-393.5) + 4 (-285.80) - (-104) kJ/mol

Δ⁰Hcomb = 2219.70 kJ/mol

n= m /MW MW c₃H₈ = 44.1 g/mol

n= 12 g/44.1 g/mol = 0.27 mol

then for 12 g the heat released will be

0.27 mol x 2219.70 kJ/mol = 600 KJ

4 0

2 years ago

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You have a substance with a length of 2 cm, width of 3 cm, and a height of 4 cm. Its density is known to be .5 g/cm3. What is th

otez555 [7]

Explanation:

They are related by the the density triangle.

Explanation:

They are related by the the density triangle.

mcdn1.teacherspayteachers.com

d =

m = d×V

V =

DENSITY

Density is defined as mass per unit volume.

d =

Example:

A brick of salt measuring 10.0 cm x 10.0 cm x 2.00 cm has a mass of 433 g. What is its density?

Step 1: Calculate the volume

V = lwh = 10.0 cm × 10.0 cm × 2.00 cm = 200 cm³

Step 2: Calculate the density

d =

433

200

= 2.16 g/cm³

MASS

d =

We can rearrange this to get the expression for the mass.

m = d×V

Example:

If 500 mL of a liquid has a density of 1.11 g/mL, what is its mass?

m = d×V = 500 mL ×

1.11

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VOLUME

d =

We can rearrange this to get the expression for the volume.

V =

Example:

What is the volume of a bar of gold that has a mass of 14.83 kg. The density of gold is 19.32 g/cm³.

Step 1: Convert kilograms to grams.

14.83 kg ×

1000

= 14 830 g

Step 2: Calculate the volume.

V =

= 14 830 g ×

19.32

= 767.6 cm³

5 0

1 year ago

An unknown metal has a mass of 86.8 g. When 5040 J of heat are added to the sample, the sample temperature changes by 64.7 ∘ C .

grandymaker [24]

Answer: The specific heat of the unknown metal is $0.897J/g^0C$

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

$Q=m\times c\times \Delta T$

Q = Heat absorbed= $5040$ Joules

m= mass of substance = 86.8 g

c = specific heat capacity = ?

Initial temperature of the water = $T_i$

Final temperature of the water = $T_f$

Change in temperature , $\Delta T=T_f-T_i=(64.7)^0C$

Putting in the values, we get:

$5040=86.8\times c\times 64.7^0C$

$c=0.897J/g^0C$

The specific heat of the unknown metal is $0.897J/g^0C$

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3 years ago