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4 years ago

11

What is the significance of an electronegativity difference of 1.7 between 2 atoms?

2 answers:

stealth61 [152]4 years ago

8 0

Explanation:

Electronegativity is defined as the ability of an atom to attract electrons towards itself.

Whereas when there is difference in values electronegativity of two different atoms then it is known as electronegativity difference.

For example, in a HCl compound the hydrogen atom is electropositive and chlorine atom is electronegative. Electronegativity value of hydrogen is 2.1 and chlorine has 3.0.

Hence, difference in their electronegativities is 3.0 - 2.1 = 0.9.

Also, it is known that when the electronegativity difference is less than or equal to 1.7 then the bond formed between the combining atoms will be polar covalent.

natta225 [31]4 years ago

7 0

It represents the boundary between what is considered to be ionic or a covalent bond.

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3 years ago

An ideal gas sealed in a rigid 4.86-L cylinder, initially at pressure Pi=10.90 atm, is cooled until the pressure in the cylinder

seraphim [82]

Answer:

$\Delta H=-11897J$

Explanation:

Hello,

In this case, it is widely known that for isochoric processes, the change in the enthalpy is computed by:

$\Delta H=\Delta U+V\Delta P$

Whereas the change in the internal energy is computed by:

$\Delta U=nCv\Delta T$

So we compute the initial and final temperatures for one mole of the ideal gas:

$T_1= \frac{P_1V}{nR}=\frac{10.90atm*4.86L}{0.082*n}=\frac{646.02K }{n} \\\\T_2= \frac{P_2V}{nR}=\frac{1.24atm*4.86L}{0.082*n}=\frac{73.49K }{n}$

Next, the change in the internal energy, since the volume-constant specific heat could be assumed as ³/₂R:

$\Delta U=1mol*\frac{3}{2} (8.314\frac{J}{mol*K} )*(73.49K-646.02K )=-7140J$

Then, the volume-pressure product in Joules:

$V\Delta P=4.86L*\frac{1m^3}{1000L} *(1.24atm-10.90atm)*\frac{101325Pa}{1atm} \\\\V\Delta P=-4756.96J$

Finally, the change in the enthalpy for the process:

$\Delta H=-7140J-4757J\\\\\Delta H=-11897J$

Best regards.

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4 years ago