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algol13
3 years ago
7

A gas balloon has a volume of 106.0 liters when the temperature is 45.0 °C and the pressure is 740.0 mm of mercury. What will it

s volume be at 20.0 °C and 780 .0 mm of mercury pressure?
Chemistry
1 answer:
Zarrin [17]3 years ago
7 0

Answer:

New volume V2 = 92.7 Liter (Approx)

Explanation:

Given:

V1 = 106 l

T1 = 45 + 273.15 = 318.15 K

P1 = 740 mm

T2 = 20 + 273.15 = 293.15 K

P2 = 780 mm

Find:

New volume V2

Computation:

P1V1 / T1 = P2V2 / T2

(740)(106) / (318.15) = (780)(V2) / (293.15)

New volume V2 = 92.7 Liter (Approx)

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What is the [H+] concentration of a solution with a pH of 3.78
lianna [129]

Answer:

[H+] = 1.66 x 10^{-4}

Explanation:

To find the [H+] concentration of a solution, we can use the formula:

[H+] = 10^{-pH}

Let's plug in the pH.

[H+] = 10^{-3.78}

Evaluate the exponent.

[H+] = 1.66 x 10^{-4}

Hope this helps!

6 0
3 years ago
In order to produce CO2, a student put a sample of calcium carbonate in a flask and added hydrochloric acid using the following
Lady_Fox [76]

Answer:

82.9% Is the percent yield

Explanation:

First, we need to balance the equation.

Ca(CO3) + 2HCl → H2O + CO2 + CaCl2

Since the problem tells you that the excess reactant is Ca(CO3), we just need to Stoichiometry to solve for the theoretical yield.

\frac{200g HCl}{1} x \frac{1 mole HCl}{36.46gHCl} x \frac{1 mol CO2}{2molHCl} x \frac{44.01CO2}{1molCO2} =120.707 g (theoretical yield)

Take your actual yield of 100g, divide that by 120.707, then multiply that decimical by 100.

4 0
3 years ago
A gas has a volume of 25.6 L at a temperature of 278 K. What will be the new temperature, in C, if
Inessa05 [86]
<h2>Hello!</h2>

The answer is: -97.37° C

<h2>Why?</h2>

According to the Charles and Gay-Lussac's Law we have that:

\frac{V}{T}=k

Where:

<em>v</em> is the volume of the gas

<em>t</em> is the temperature of the gas

<em>k </em>is the proportionality constant

From the Gay-Lussac's Law we also have the following relation:

\frac{V1}{T1}=\frac{V2}{T2}

Since we need to find the new temperature (T2) we can use the last equation:

\frac{V1}{T1}=\frac{V2}{T2}\\\\T2=\frac{V2*T1}{V1}=\frac{16.2L*278K}{25.6L}=175.92K

We are asked to find the temperature in Celsius degrees, so, we must convert the result (in K) to Celsius degrees:

Celsius=K-273.15=175.92-273.15=-97.37

So, the temperature is -97.37° C

Have a nice day!

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3 years ago
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