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meriva
2 years ago
7

Which is the correct mole ratio of

Chemistry
1 answer:
nika2105 [10]2 years ago
5 0

The correct mole ratio of K₃PO₃ and KNO₂ in the chemical reaction is 1 : 3

<h3>Balanced equation</h3>

3Mg(NO₂)₂ (aq) + 2K₃PO₃ (aq) -> Mg₃(PO₃)₂(aq) + 6KNO₂(aq)

from the balance equation,

  • The number of mole of K₃PO₃ = 2 moles
  • The number of mole of KNO₂ = 6 moles

<h3>How to determine the mole ratio of K₃PO₃ and KNO₂</h3>
  • Number of mole of K₃PO₃ = 2 moles
  • Number of mole of KNO₂ = 6 moles
  • Mole ratio of K₃PO₃ and KNO₂ =?

Mole ratio = mole of K₃PO₃ / mole of KNO₂

Mole ratio of K₃PO₃ and KNO₂ = 2 / 6

Mole ratio of K₃PO₃ and KNO₂ = 1 : 3

Learn more about stoichiometry:

brainly.com/question/14735801

#SPJ1

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3 years ago
How many moles are in 68.5 liters of oxygen gas at STP?
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Since we know that one mole of any gas at STP is equal to 22.4 L we can multiply 135L by the following conversion: 1 mole/22.4L. When you set up the problem it looks like this…: (135L)x 1 mole/22.4L =6.03 moles of oxygen gas The liters cancel out and you are left with moles as your units.


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3 0
3 years ago
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How fast must a 56.5-g tennis ball travel in order to have a de Broglie wavelength that is equal to that of a photon of green li
nikklg [1K]

Answer:vv

v=2.17\times 10^{-26}\ m/s

Explanation:

The expression for the deBroglie wavelength is:

\lambda=\frac {h}{m\times v}

Where,  

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h is Plank's constant having value 6.626\times 10^{-34}\ Js

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Wavelength = 5400 Å = 5400\times 10^{-10}\ m

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5400\times 10^{-10}=\frac{6.626\times 10^{-34}}{0.0565\times v}

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7 0
3 years ago
Find the oxidizing agent and the reducing agent.
Vladimir [108]
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(2)  C(s) + O2(g) --> CO2(g)

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The charge of O in O2 is 0 while in CO2, its charge is -2. O is reduced. Hence, it is the oxidizing agent.

(3)  2MnO⁻⁴ + SO2 + 2H2O --> 2Mn²⁺ + 5SO2⁻⁴ 4H⁺

The charge of Mn in MnO⁻⁴ is 4+ while its charge in Mn²⁺ is 2+. Mn is reduced. Hence, it is the oxidizing agent.

The charged of S in SO2 is -4 while its charge in SO₂⁻⁴ is 0. S is oxidized. Hence, it is the reducing agent. 
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