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meriva
2 years ago
7

Which is the correct mole ratio of

Chemistry
1 answer:
nika2105 [10]2 years ago
5 0

The correct mole ratio of K₃PO₃ and KNO₂ in the chemical reaction is 1 : 3

<h3>Balanced equation</h3>

3Mg(NO₂)₂ (aq) + 2K₃PO₃ (aq) -> Mg₃(PO₃)₂(aq) + 6KNO₂(aq)

from the balance equation,

  • The number of mole of K₃PO₃ = 2 moles
  • The number of mole of KNO₂ = 6 moles

<h3>How to determine the mole ratio of K₃PO₃ and KNO₂</h3>
  • Number of mole of K₃PO₃ = 2 moles
  • Number of mole of KNO₂ = 6 moles
  • Mole ratio of K₃PO₃ and KNO₂ =?

Mole ratio = mole of K₃PO₃ / mole of KNO₂

Mole ratio of K₃PO₃ and KNO₂ = 2 / 6

Mole ratio of K₃PO₃ and KNO₂ = 1 : 3

Learn more about stoichiometry:

brainly.com/question/14735801

#SPJ1

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VLD [36.1K]
<h2>The required "option is b) potential energy".</h2>

Explanation:

  • The energy which is associated with the motion of the object is called kinetic energy.
  • The energy which is associated with the amount of heat released is known as thermal energy.
  • The energy which is released during a chemical reaction is known as chemical energy.

          Therefore, option (a), (c), and (d) are incorrect.

  • The energy which is possessed by a stationary object or associated with the position of an object is called as potential energy.
  • Hence, the correct option is potential energy.
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3 years ago
Give the name of the following molecule. A compound with a total of 10 carbons with one double bond and the rest single bonds. T
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Answer:
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Explanation:

First of all draw a straight chain of 8 carbon atoms.

Make a double bond between carbon number 6 and 7 numbering from left.

Add ethyl group at position 3 starting from left.

The structure sketched is attached below,

According to rules the longest chain containing a double bond is selected. Numbering is started from the end to which double bond is nearer. So, in our case the double bond starts at carbon 2, hence parent name of compound is 2-Octene. Then the substituent at position 6 is named.

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<span>The answer is A. In chemistry, Gibbs Free Energy is defined as the enthalpy of the system minus the product of the temperature times the entropy of the system. To write it as a formula, G = H - TS, delta G=delta H-T*delta S, where delta denotes the change.</span>
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p = latm

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R= 0.08206 L atm mol K

75.0g02

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Ideal gas law: PV = nRT, solve for volume: V = nRT P

V =

4.6875mol 0.08206 L-atm mol. K · 273.15K

V = 105L

latm

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