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meriva
2 years ago
7

Which is the correct mole ratio of

Chemistry
1 answer:
nika2105 [10]2 years ago
5 0

The correct mole ratio of K₃PO₃ and KNO₂ in the chemical reaction is 1 : 3

<h3>Balanced equation</h3>

3Mg(NO₂)₂ (aq) + 2K₃PO₃ (aq) -> Mg₃(PO₃)₂(aq) + 6KNO₂(aq)

from the balance equation,

  • The number of mole of K₃PO₃ = 2 moles
  • The number of mole of KNO₂ = 6 moles

<h3>How to determine the mole ratio of K₃PO₃ and KNO₂</h3>
  • Number of mole of K₃PO₃ = 2 moles
  • Number of mole of KNO₂ = 6 moles
  • Mole ratio of K₃PO₃ and KNO₂ =?

Mole ratio = mole of K₃PO₃ / mole of KNO₂

Mole ratio of K₃PO₃ and KNO₂ = 2 / 6

Mole ratio of K₃PO₃ and KNO₂ = 1 : 3

Learn more about stoichiometry:

brainly.com/question/14735801

#SPJ1

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There are 8.61 × 10²⁰ atoms in 0.290 g P₂O₅.

Step 1. Convert <em>grams of P₂O₅ to moles of P₂O₅</em>.

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Step 2. Convert <em>moles of P₂O₅ to molecules of P₂O₅</em>.

\text{Molecules of } \text{P}_{2}\text{O}_{5} = \text{0.002 043 mol } \text{P}_{2}\text{O}_{5} \times \frac{6.022 \times 10^{23}\text{ molecules }\text{P}_{2}\text{O}_{5}}{\text{1 mol } \text{P}_{2}\text{O}_{5}}\\

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There are seven atoms in 1 mol P₂O₅.

∴ \text{Total atoms} = 1.23\times 10^{21 }\text{ molecules }\text{P}_{2}\text{O}_{5} \times\frac{\text{7 atoms}}{\text{1 molecule }\text{P}_{2}\text{O}_{5}} = 8.61 \times 10^{21}\text{ atoms}\\

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