Wich has more energy rolling down a hill - a bowling ball or soccer ball? Explain your answer
2 answers:
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6.6 × J = 6.2 ×
British thermal units
First of all, we should know that 1 British thermal unit = 1055 Joules.
From question, heat = 6.6 × J
1 BTU = 1055 J
6.6 × J =
× 6.6 ×
British thermal units
= 6.2 × British thermal units
1000 Joules = 1 kilojoule
A kilojoule is a unit of measure of energy, in the equal way that kilometers degree distance. meals energy used to be measured in energy and some international locations still use those gadgets.
The power we get from foods and drinks is measured in kilojoules. that is the metric time period for calorie. Kilojoules and energy constitute the equal aspect. One calorie is ready four kilojoules.
Calorie a unit for measuring warmth same to the quantity of warmth required to elevate the temperature of one gram of water one diploma Celsius.
Learn more about kilojoules here :- brainly.com/question/490326
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The question is incomplete. There's missing the image, which is shown below.
Answer:
Volume of O₂ = 6 L, volume of mixture: 18 L, volume of H₂O = 12 L, molecule volume of H₂O = 0.667 molecule/L
Explanation:
The reaction between hydrogen gas and oxygen gas to form water is:
2H₂(g) + O₂(g) → 2H₂O(g)
So, for 1 mol of O₂ is necessary 2 moles of H₂ form 2 moles of H₂O. As the images below there's 8 molecules of H₂, 4 molecules of O₂, 12 molecules in the mixture, and 8 molecules of H₂O. Thus, there are stoichiometric values.
All the images are at the same temperature and pressure, so, by the ideal gas law:
PV= nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.
The number of moles and molecules are related, so let's substitute it in the equation. For the H₂:
P*12 = 8*RT
RT/P = 12/8 = 1.5
Thus, for O₂:
PV= nRT
V = n*(RT/P)
V = 4*1.5 = 6 L
For the mixture:
V = 12*1.5 = 18 L
For H₂O:
V = 8*1.5 = 12 L
The molecule volume is the number of molecules divided by the volume they occupy, thus for water: 8/12 = 0.667 molecules/L
