102 grams of ammonia is formed when 3 moles of nitrogen and 6.7 moles of hydrogen reacts.
Explanation:
The equation given is of Haeber's process in which the nitrogen is limiting factor in the ammonia formation and hydrogen if in excess gets delimited.
We know that 1 mole of Nitrogen gives 2 moles of ammonia.
We have 3 moles of nitrogen here,
So, 6 moles of ammonia will be form
so from the formula
no of moles=mass/atomic mass
mass= no. of moles*atomic mass
= 6*17
= 102 grams of ammonia will be formed.
So, 6 moles or 102 grams of ammonia is formed when 3 mole of nitrogen and 6.7 mole of hydrogen reacts.
B) Cu(OH) 2 Is the resulting answer when H20 is decomposed.
Answer:
The boiling point of noble gas increases as you go down the group because the London dispersion forces increase.
Atomic number = 20 -------> Ca (calcium)
Calcium has four shells (1, 2, 3, 4) and two sublevels ( s, p ).
1s² 2s² 2p⁶ 3s² 3p⁶ 4s²
