Answer is: 315,29 grams of copper ore.
m(<span>chalcopyrite) = ?
</span>ω(CuFeS₂) = 55,0 % = 0,55.
<span>m(Cu) = 60,0 g.
mass percentage of copper in </span>CuFeS₂:
ω(Cu) = Ar(Cu) ÷ Mr(CuFeS₂).
ω(Cu) = 63,55 ÷ 183,4.
ω(Cu) = 0,346 = 34,6 %.
mass percentage of copper in chalcopyrite:
ω(Cu) : ω₁(Cu) = 100% : ω(CuFeS₂).
ω₁(Cu) = 19,03 % = 0,1903.
m(chalcopyrite) = 60,0 g ÷ 0,1903.
m(chalcopyrite) = 315,29 g.
Answer:
answer: Pure dry crystals of zinc chloride can be produced by crystallisation, then filtration to remove excess solution, followed by drying on a watch glass or in a warm oven.
answer- Yes. The reaction of hydrochloric acid with zinc oxide to form zinc chloride and water is a neutralization reaction because acid (HCl) is a neutralizing base (ZnO).
A substance that increases rate of rxn by changing orientation of molecules and/or activation energy. both increase effectivity of collisions.
The chemical formula of sulfur hexabromide is SBr6. From the name sulfur hexabromide, you will know that it has one sulfur atoms and six bromine atoms due to the prefix hexa-. Little is known about this substance and it is not being utilized in any industry currently.