Answer:
E. 3h
Explanation:
We know that
u = 0 m/s.
velocity after t = 1s
v = u+gt = 0+9.81 x 1s= 9.81 m/s
distance covered in 1st sec
= =>> ut+0.5 x g x t²
=>>0 + 0.5x 9.81 x 1 = 4.90m
Let 4.90 be h
distance travelled in 2nd second will now be used
So velocity after t = 1s
=>>1 x t+ 0.5 x g x t²
=>9.81x 1 + 0.5 x 9.81 x 1 = 3 x 4.90
So since h= 4.90
Then the ans is 3x h = 3h
λ = 3.125 m
λ = 2.83 m
<h3>Further explanation</h3>
Given
Frequency of radio : 96 MHz and 106 MHz
Required
The wavelength
Solution
Wavelength : from the crest to the crest of the next wave or the trough to the trough
Frequency (f): number of waves in one second
v = λ x f
λ = v : f
Input the value :
f = 96 MHz = 96 x 10⁶ Hz
λ = v : f
λ = 3 x 10⁸ : 96 x 10⁶
λ = 3.125 m
f = 106 MHz = 106 x 10⁶ Hz
λ = v : f
λ = 3 x 10⁸ : 106 x 10⁶
λ = 2.83 m
Answer:
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Explanation:
Explanation:
The electro magnetic force is given by
F = 
where
and
are charged particles
k =Coulombs constant
r = distance between two charges
And gravitational force is given by
F = 
where
and
are masses
G =Garvitation constant
r = distance between two masses
Now since the planets, stars and galaxies are electrically neutral, therefore they have zero electrical charge and so electro magnetic forces have no affect on these planets, stars and heavenly bodies.
Whereas the masses of the heavenly bodies are very large, so they are largely affected by the gravitational force since Gravitational force is directly proportional to the product of the masses of a body.
Therefore, though the electromagnetic force is stronger than the gravitational force, the electromagnetic force does not dominate the forces in the heavenly bodies as they as not electrically charged.