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Romashka [77]
3 years ago
13

A snail travels 300 cm in 4 minutes.calculate speed of snail in m/s

Physics
1 answer:
LekaFEV [45]3 years ago
5 0

Answer:

\frac{0.0125m}{s}

Explanation:

In order to solve this question we need to know that  speed = \frac{distance}{time}. Then we need to convert 4 minutes into seconds and cm into m. We can do that by multiplying the number of minutes by 60 (because there is 60 seconds in one minute) and dividing the number of cm by 100 (because there is 100 cm in one m). So.......

4min = 4 x 60s = 240s

300cm = 300/100 m = 3m

Now we know that distance = 300m, and that the time = 4min = 240s ⇒

⇒ speed=\frac{distance}{time} = \frac{3m}{240s} = \frac{0.0125m}{s}

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Electrical resistance is measured in
devlian [24]
Resistance is the ratio of
 
         (voltage between two points in the circuit)
divided by
         (current between the same points).

It's expressed in units of Ohms, so the correct choice is "none of the above".
8 0
3 years ago
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What is the kinetic energy of a 1500 kg object that is moving at a speed of 71 meters per second​
Fynjy0 [20]

Answer:

3.78075x10^6 kg x meter^2/ second^2

Explanation:

Kinetic energy  K= 1/2 x mass x velocity^2

4 0
3 years ago
saad has mass 80 kg when resting on the ground at the equator . what will be the centripetal acceleration on saad if the radius
Molodets [167]
Here,
         m=80 kg
         R= 6.4*10^6 m
       and t=24*3600=86400 s

Centripetal acceleration:
      a=ω²r
         =(2\pi /86400)^2 * 6.4*10^6
         =0.034 m/s²
6 0
3 years ago
Standing at a crosswalk, you hear a frequency of 530 Hz from the siren of an approaching ambulance. After the ambulance passes,
malfutka [58]

Answer:

_s = 37.77 m / s

Explanation:

This is an exercise of the Doppler effect that the change in the frequency of the sound due to the relative speed of the source and the observer, in this case the observer is still and the source is the one that moves closer to the observer, for which relation that describes the process is

                    f ’= f₀  \frac{v}{v - v_s}

where d ’= 530 Make

when the ambulance passes away from the observer the relationship is

                    f ’’ = f₀ \frac{v}{v + v_s}

where d ’’ = 424 beam

let's write the two expressions

               f ’ (v-v_s) = fo v

               f ’’  (v + v_s) = fo v

let's solve the system, subtract the two equations

                v (f ’- f’ ’) - v_s (f’ + f ’’) = 0

                v_s = v \frac{ f' - f''}{ f' + f''}

the speed of sound is v = 340 m / s

let's calculate

                 v_s = 340 (\frac{ 530 -424}{530+424} )

                 v_s = 340 (\frac{106}{954})

                  v_s = 37.77 m / s

5 0
2 years ago
If diameter and length of a cylinder are 0.01 m and 0.07 m respectively, the thermal conductivity of air is 0.028 W/mK and the N
kap26 [50]

Answer:

The convective heat transfer coefficient of the fluid is 170.4 watts per square meter-degree Celsius.

Explanation:

The Nusselt number (Nu) is a dimensionless factor which compares the sensitivity of a fluid due to convection with those due to conduction:

Nu = \frac{h\cdot L_{c}}{k} (Eq. 1)

Where:

h - Convective heat transfer coefficient, measured in watts per square meter-degree Celsius.

k - Conductive heat transfer coefficient, measured in watts per meter-degree Celsius.

L_{c} - Characteristic length, measured in meters.

In addition, the characteristic length of a cylinder is defined by the following formula:

L_{c} = \frac{\pi\cdot r^{3}\cdot l}{2\pi\cdot r^{2}+2\pi\cdot r \cdot l} (Eq. 2)

Where:

r - Radius of the cylinder, measured in meters.

l - Length of the cylinder, measured in meters.

If we know that Nu = 14.2, k = 0.028\,\frac{W}{m\cdot ^{\circ}C}, r = 0.005\,m and l = 0.07\,m, then the convective heat coefficient is:

From (Eq. 2):

L_{c} = \frac{\pi\cdot (0.005\,m)^{2}\cdot (0.07\,m)}{2\pi\cdot (0.005\,m)^{2}+2\pi\cdot (0.005\,m)\cdot (0.07\,m)}

L_{c} = \frac{7}{3000}\,m

And by (Eq. 1):

h = \frac{k\cdot Nu}{L_{c}}

h = \frac{\left(0.028\,\frac{W}{m\cdot ^{\circ}C} \right)\cdot (14.2)}{\frac{7}{3000}\,m }

h = 170.4\,\frac{W}{m^{2}\cdot ^{\circ}C}

The convective heat transfer coefficient of the fluid is 170.4 watts per square meter-degree Celsius.

7 0
2 years ago
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