Each pole would become tropical during summer, but be horribly cold during winter, far colder than they are now. But the equator would be in perpetual twilight during two seasons—and summer the opposing two.
Answer:
Explanation:
Energy of radiation in eV = 1237.5/280 = 4.42 eV.
Work function = 2.65 eV.
Maximum kinetic energy = 4.42 - 2.65 = 1.77 eV.
<span>The chemical properties of ANY atom are found in how they react with other elements.
A. An element's symbol - Nothing to do with reactions
B. The average atomic mass -The mass doesn't react
C. The number of electrons that occupy the outer shell - the only part of the electrons that move, SO they are involved in the reactions (answer)
D. The total number of electrons - The inner electrons cannot move from the atom unless there is ALOT of energy given to them, so these cannot react and would not contribute to the chemical properties.</span>
Since waves are moving, we define frequency as the number of waves that pass a given point in a specified unit of time. The unit commonly used is Hertz which is the number of wave cycles that pass a point in one second.
Answer:
Efriction = 768.23 [kJ]
Explanation:
In order to solve this problem we must use the principle of energy conservation. Where it tells us that the energy of a system plus the work applied or performed by that system, will be equal to the energy in the final state. We have two states the initial at the time of the balloon jump and the final state when the parachutist lands.
We must identify the types of energy in each state, in the initial state there is only potential energy, since the reference level is in the ground, at the reference point the potential energy is zero. At the time of landing the parachutist will only have potential energy, since it reaches the reference level.
The friction force acts in the opposite direction to the movement, therefore it will have a negative sign.
where:
m = mass = 56 [kg]
h = elevation = 1400 [m]
v = velocity = 5.6 [m/s]
![(56*9.81*1400)-E_{friction}=\frac{1}{2}*56*(5.6)^{2}\\769104 -E_{friction}= 878.08 \\E_{friction}=769104-878.08\\E_{friction}=768226[J] = 768.23 [kJ]](https://tex.z-dn.net/?f=%2856%2A9.81%2A1400%29-E_%7Bfriction%7D%3D%5Cfrac%7B1%7D%7B2%7D%2A56%2A%285.6%29%5E%7B2%7D%5C%5C769104%20-E_%7Bfriction%7D%3D%20878.08%20%5C%5CE_%7Bfriction%7D%3D769104-878.08%5C%5CE_%7Bfriction%7D%3D768226%5BJ%5D%20%3D%20768.23%20%5BkJ%5D)
