Question

A heat engine operates in a Carnot cycle between 75◦C and 492◦C. It absorbs 19300 J of energy per cycle from the hot reservoir. The duration of each cycle is 1.16 s. What is the mechanical power output of this engine? Answer in units of kW.

Answer 1

Answer:

9.069 KW

Explanation:

The heat engine operates in a carnot cycle between 75°C to 492°C  so the lower temperature $T_L=75^{\circ}C=273+75=348K$ and the higher temperature $T_H=492^{\circ}C=273+492=765K$

Efficiency of the carnot cycle $\eta =1-\frac{T_L}{T_H}=1-\frac{348}{765}=0.545$

We know that $\eta =\frac{work\ done }{heat\ absorbed}$

$work\ done=\eta \times heat\ abosorbed=0.545\times 19300=10520.392\ J$

it is given that duration of each cycle is 1.16 sec so power output $P=\frac{W}{T}=\frac{10520.392}{1.16}=9069.30\ W=9.069\ KW$