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Setler [38]
4 years ago
14

A heat engine operates in a Carnot cycle between 75◦C and 492◦C. It absorbs 19300 J of energy per cycle from the hot reservoir.

The duration of each cycle is 1.16 s. What is the mechanical power output of this engine? Answer in units of kW.
Physics
1 answer:
Nitella [24]4 years ago
6 0

Answer:

9.069 KW

Explanation:

The heat engine operates in a carnot cycle between 75°C to 492°C  so the lower temperature T_L=75^{\circ}C=273+75=348K and the higher temperature T_H=492^{\circ}C=273+492=765K

Efficiency of the carnot cycle \eta =1-\frac{T_L}{T_H}=1-\frac{348}{765}=0.545

We know that \eta =\frac{work\ done }{heat\ absorbed}

work\ done=\eta \times heat\ abosorbed=0.545\times 19300=10520.392\ J

it is given that duration of each cycle is 1.16 sec so power output P=\frac{W}{T}=\frac{10520.392}{1.16}=9069.30\ W=9.069\ KW

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Answer:

All living organisms need energy to grow and reproduce, maintain their structures, and respond to their environments. Metabolism is the set of life-sustaining chemical processes that enables organisms transform the chemical energy stored in molecules into energy that can be used for cellular processes.

Explanation:

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3 years ago
1. Calcular la masa de mercurio que pasó de 30 °C hasta 120 °C y absorbió 4400 cal. Calor específico del
timofeeve [1]

Answer:

Masa, m = 0.088 kg

Explanation:

Given the following data;

Temperatura inicial = 30°C

Temperatura final = 120°C

Capacidad calorífica específica = 138J/kg.K

Calor absorbido, Q = 4400 cal.

Para encontrar la masa;

La capacidad calorífica viene dada por la fórmula;

Q = mct

Dónde;

Q representa la capacidad calorífica o la cantidad de calor.

m representa la masa de un objeto.

c representa la capacidad calorífica específica del agua.

dt representa el cambio de temperatura.

dt = T2 - T1

dt = 120 - 30

dt = 90°C to kelvin = 273 + 90 = 363K

Sustituyendo en la fórmula, tenemos;

4400 = m*138*363

4400 = 50094m

m = \frac {4400}{50094}

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How does the sun provide us with the energy we need to run our bodies?
ivanzaharov [21]
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It's like this:
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3 years ago
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A ball starts at rest and rolls down a ramp, developing a speed of 45 m/s in 7 seconds. Calculate the ball's acceleration.
Alexxx [7]

Answer:

6.429 m/s^2.

Explanation:

Using equations of motion,

i. vf = vi + at

ii. vf^2 = vi^2 + 2a*S

iii. S = vi*t + 1/2 * (a*t^2)

Where,

vf = final velocity of the motion

vi = initial velocity of the motion

S = distance travelled

t = time taken to complete the motion

a = acceleration due to gravity

Given:

vi = 0m/s

vf = 45 m/s

t = 7 s

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Using the i. equation of motion,

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a = 45/7

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3 years ago
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