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3 years ago

If the earth’s tilt on it axis were to increase by 20 degrees, what would happen to earth?

1 answer:

4 0

Each pole would become tropical during summer, but be horribly cold during winter, far colder than they are now. But the equator would be in perpetual twilight during two seasons—and summer the opposing two.

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A 20 MHz carrier is frequency modulated by a sinusoidal signal such that the maximum frequency deviation is 100kHz. Calculate th

Ivan

Answer:

Idk

Explanation:

6 0

3 years ago

Work out the current through a television with a power of 0.8 kW if it uses the 230 V mains supply. Give your answer to 1 decima

Y_Kistochka [10]

Answer:

the current is 3.5 A

Explanation:

The computation of the current is shown below:

As we know that

Current [A] = Electrical power [W] ÷ Potential difference [V]

Now convert KW TO W = × 1000

So, the current is

= 800W ÷ 230V

= 3.5 A

Hence, the current is 3.5 A

8 0

3 years ago

What is the critical angle and how does it relate to total internal reflection?

liubo4ka [24]

Answer:

critical angle is the angle of incidence in optically denser medium, for which the angle of reflection in the less denser medium is 90 degree

Explanation:

total internal reflection occurs at one particular angle of incidence where the reflected ray lies on the boundary.

this angle is called the critical angle

6 0

3 years ago

A .183 kg ball is moving 18.8 m/s when it runs into a spring of spring constant 86.9 N/m. How much KE does the ball have when it

Lemur [1.5K]

Answer:

The value is $KE_B = 20.59 \ J$

Explanation:

From the question we are told that

The mass of the ball is $m = 183 \ kg$

The initial speed of the ball is $u = 18.8 \ m/s$

The spring constant is $k = 86.9 \ N/m$

The compression distance is $x = 0.520 \ m$

Generally the energy stored in the string is mathematically represented as

$E = \frac{1}{2} * k * x^2$

=> $E = \frac{1}{2} * 86.9 * 0.520 ^2$

=> $E = 11.75 \ J$

Generally the kinetic energy of the ball is mathematically represented as

$KE_b = \frac{1}{2} * m * u^2$

=> $KE_b = \frac{1}{2} * 0.183 * (18.8 )^2$

$KE_b = 32.34 \ J$

Generally the KE the ball have when it has compressed the spring is mathematically represented as

$KE_B = KE_b - E$

=> $KE_B = 32.34 - 11.75$

=> $KE_B = 20.59 \ J$

7 0

3 years ago

A mover uses a ramp to load a crate of nails onto a truck. The crate, which must be lifted 1.5 m from the street to the bed of t

jonny [76]

Answer:

Explanation:

Using the efficiency formula. Efficiency = MA/VR * 100%

MA = Mechanical Advantage

VR = velocity ratio = $\frac{distance\ moved\ by\ effort}{distance\ moved\ by\ load}$

Distance moved by effort = 4.5m

distance moved by load = 1.5m

VR = 4.5/1.5 =3

Assuming efficiency is 100% (since friction can be ignored)

100% = MA/3 * 100%

1 = MA/3

MA = 3*1

MA = 3

Mechanical Advantage of the ramp is 3

8 0

4 years ago