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pishuonlain [190]
3 years ago
7

Which of the following lenses has at least one plane surface?

Physics
2 answers:
hram777 [196]3 years ago
4 0
<h3><u>Answer;</u></h3>

Plano-convex lens

<h3><u>Explanation;</u></h3>
  • Plano-convex lens has at least one plane surface
  • <em><u>Plano-convex lenses are types of lenses that have one spherical surface and one flat surface. </u></em>
  • These types of lenses are designed for infinite conjugate use or simple imaging in non-critical applications. The  lenses are ideal for all-purpose focusing elements.
  • For example; they are ideal for beam expansion, light projection, or for expanding an optical system's focal length.
myrzilka [38]3 years ago
3 0
<span>d. plano-convex lens</span>
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A table is moved using 60 N of force.
dem82 [27]

Answer:

15m

Explanation:

W=f×s

s =  \frac{w}{f} \\ s =  \frac{900j}{60n} \\ s = 15m

5 0
3 years ago
5.0 kg, with a bullet of mass 0.1 kg. The target was mounted on
kari74 [83]

Answer:

306 m/s

Explanation:

Law of conservation of momentum

m1v1 + m2v2 = (m1+m2)vf

m1 is the bullet's mass so it is 0.1 kg

v1 is what we're trying to solve

m2 is the target's mass so it is 5.0 kg

v2 is the targets velocity, and since it was stationary, its velocity is zero

vf is the velocity after the target is struck by the bullet, so it is 6.0 m/s

plugging in, we get

(0.1 kg)(v1) + (5.0 kg)(0 m/s) = (0.1 kg + 5.0 kg)(6.0 m/s)

(0.1)(v1) + 0 = 30.6

(0.1)(v1) = 30.6

v1 = 306 m/s

8 0
3 years ago
Suppose that two objects attract each other with a gravitational force of 16 units. If the distance between the two objects is r
Naddik [55]

Explanation:

Fgravity = G*(mass1*mass2)/D²

G is the gravitational constant throughout the universe.

D is the distance between both objects.

D is now reduced by a factor of 5, meaning Dnew = D/5 we get

Fgravitynew = G*(mass1*mass2)/(D/5)² =

= G*(mass1*mass2)/(D²/25) =

= 25* G*(mass1*mass2)/D² = 25* Fgravity

the new force of gravity/attraction is 25×16 = 400 units.

4 0
3 years ago
in an automobile crash, a vehicle that was stopped at a red light is rear-ended by another vehicle. The vehicles have the same m
baherus [9]

The initial speed of the vehicle before the collision is 8 m/s.

  • Let the mass of the vehicle = m
  • Let the initial speed of the vehicle stopped = u
  • The initial speed of the vehicle parked at the red light = 0

<h3>Principle of conservation of linear momentum</h3>
  • The initial speed of the vehicle before the collision is calculated by applying principle of conservation of linear momentum as follows;

m_1 u_1 + m_2 u_2 = v(m_1 + m_2)\\\\mu + m(0) = 4(m+ m)\\\\mu = 4(2m)\\\\mu = 8m\\\\u = 8 \ m/s

Thus, the initial speed of the vehicle before the collision is 8 m/s.

Learn more about inelastic collision here: brainly.com/question/7694106

6 0
3 years ago
A certain piece of metal (density 9.45 grams per cubic centimeter) has the shape of a hockey puck with a diameter of 13 cm and a
atroni [7]

Answer:

0.0195 m

Explanation:

\rho _{p} = density of hockey puck = 9.45 gcm⁻³ = 9450 kgm³

d_{p} = diameter of hockey puck = 13 cm = 0.13 m

h_{p} = height of hockey puck = 2.8 cm = 0.028 m

\rho _{m} = density of mercury = 13.6 gcm⁻³ = 13600 kgm³

d = depth of puck below surface of mercury

According to Archimedes principle, the weight of puck is balanced by the weight of mercury displaced by puck

Weight of mercury displaced = Weight of puck

\rho _{m} (0.25)(\pi d_{p}^{2} d ) g = \rho _{p} (0.25)(\pi d_{p}^{2} h_{p} ) g\\\rho _{m} ( d ) = \rho _{p} ( h_{p} )\\(13600) d = (9450) (0.028)\\d = 0.0195 m

7 0
3 years ago
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