therefore the frequency = 6×10^14
Answer:
I've implemented this program using python
userinput = int(input("Length: "))
mylist = []
mylist.append(userinput)
for i in range(1,userinput+1):
userinp = int(input("Input: "))
mylist.append(userinp)
smallval = mylist[1]
for i in range(1,len(mylist)):
if smallval > mylist[i]:
smallval = mylist[i]
for i in range(1,len(mylist)):
mylist[i] = mylist[i] - smallval
for i in range(1,len(mylist)):
print(mylist[i],end=' ')
Explanation:
I've added the full source program as an attachment where I used comments to explain difficult lines
Answer:
Following are the solution to the given question:
Explanation:
Since a procedure has the Read10 parameter, the 10 characters from the input file are stored in the BYTE array as myString. The LOOP instruction, which includes indirect addressing and also the call to the ReadChar method, please find the attached file of the procedure:
Answer:
The answer is "5.5 and 90.90%"
Explanation:
For point 1:
To calculate the speed from fast mode, its run time without enhancement should be worked out. Designers are aware of which two selves are implicated throughout the accelerated project planning: the empty (
) and the increased stages (
).
Although not enhanced, this would take almost as long (
) and for the combine to give phase; even so, the increased phase would've been 10 times longer, as well as
. Thus the corresponding total speed without enhancement is 
Its overall speed is:

For point 2:
We re-connect these figures in Amdahl's Law throughout order to identify how long it would take for both the initial implementation:


To make it useable, the disk first needs to be subdivided into logical volumes, then formate, so that it is readable by the systems.