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zhenek [66]
3 years ago
12

How is a model of an atom different from a real atom? A. A model of an atom is not as big as an actual atom. B. A model of an at

om is the same as a real atom. C. A model of an atom is more complex than a real atom. D. model of an atom is not as small as an actual atom.
Chemistry
1 answer:
tatyana61 [14]3 years ago
5 0
The option that would best contrast the real and the model atoms is letter "D. model of an atom is not as small as an actual atom". The size of an atom is said to be no more than 0.1 to 0.5 nanometers. The models are used to proper illustrate the atom's physical attributes. That is why, it needs to be bigger in size. 
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True or False: Every acid has to have a carbon in its chemical formula.
Tcecarenko [31]
True ^^ they explained it well
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3 years ago
Type here. 5. What is the relationship between the amount of force in Newtons applied to the spring and the elastic potential?​
worty [1.4K]

Answer:

"The higher the spring constant, the stiffer the spring. The spring constant is not the same value for different elastic objects. For a given spring and other elastic objects, the extension is directly proportional to the force applied. For example, if the force is doubled, the extension doubles."

Explanation:

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3 years ago
A 1.0 M solution of a compound with 2 ionizable groups (pKa's = 6.2 and 9.5; 100 mL total) has a pH of 6.8. If a biochemist adds
juin [17]

Answer:

pH = 9,32

Explanation:

The compound with 2 ionizable groups has the following equilibriums:

H₂M ⇄ HM⁻ + H⁺ pka = 6,2

HM⁻ ⇄ M²⁻ + H⁺ pka = 9,5

The reaction of M²⁻ with HCl is:

M²⁻ + HCl → HM⁻ + Cl⁻

The moles of M²⁻ are:

0,100L×1,0M = 0,1moles

And moles of HCl are:

0,060L×1,0M = 0,06moles

That means that moles of M²⁻ will be 0,1-0,06 = 0,04mol and moles of HM⁻ will be the same than HCl, 0,06mol

Using Henderson-Hasselbalch formula:

pH = pka + log₁₀ [M²⁻] / [HM⁻]

Replacing:

pH = 9,5 + log₁₀ [0,04] / [0,06]

<em>pH = 9,32</em>

<em></em>

I hope it helps!

4 0
4 years ago
Using the van der Waals equation, calculate the pressure for a 1.25 mol sample of xenon contained in a volume of 1.000L at 75°C
alina1380 [7]

Answer:

ABC

Explanation:

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5 0
3 years ago
36. Write a balanced chemical equation for each chemical reaction. (a) Solid copper reacts with solid sulfur to form solid coppe
stiks02 [169]

Answer:

a) 2Cu(s) + S(s) → Cu₂S(s)

b) 2SO₂(g) + O₂(g) → 2SO₃(g)

c) 4HCl(aq) +  MnO₂(s) → MnCl₂(aq) + 2H₂O(l) + Cl₂(g)

d) C₆H₆(l) + 15/2 O₂(g) → 6CO₂(g) + 3H₂O(l)

Explanation:

First, we have to write the chemical formulas for reactants and products. Then, to identify which is the state of matter of each compound (liquid: l, solid: s, aqueous: aq, gas: g). Finally, we write the equation and balance the atoms.

a) Solid copper reacts with solid sulfur to form solid copper(I) sulfide.

<u>Reactants</u>: solid copper (Cu(s)) and solid sulfur (S(s))<em>. </em><u>Product</u>: copper(I) sulfide (Cu₂S) because sulfur anion has two negative charges (S⁻²) and we need two copper ions with one positive charge (Cu⁺) to obtain the neutral compound.

The balanced requires a coefficient of 2 for Cu(s) to balance the 2 Cu atoms on the products side:

2Cu(s) + S(s) → Cu₂S(s)

(b) Sulfur dioxide gas reacts with oxygen gas to form sulfur trioxide gas.

<u>Reactants</u>: sulfur dioxide (SO₂) and oxygen gas (which is a diatomic molecule: O₂). <u>Products</u>: sulfur trioxide gas (SO₃(s)).

The balanced equation is:

2SO₂(g) + O₂(g) → 2SO₃(g)

We need a coefficient of 2 for SO₂ and SO₃ to balance O and S atoms.

(c) Aqueous hydrochloric acid reacts with solid manganese(IV) oxide to form aqueous manganese(II) chloride, liquid water, and chlorine gas.

<u>Reactants</u>: aqueous hydrochloric acid (HCl(aq)) and solid manganese (IV) oxide (MnO₂(s), because we need two oxygen anions O²⁻ to neutralize 4 positive charges in Mn IV). <u>Products</u>: aqueous manganese(II) chloride (MnCl₂, because we need two chloride ions Cl⁻ to neutralize two positive charges in Mn(II)), liquid water (H₂O), and chlorine gas (Cl₂, because it is a diatomic molecule).

The balanced chemical equation is:

4HCl(aq) +  MnO₂(s) → MnCl₂(aq) + 2H₂O(l) + Cl₂(g)

(d) Liquid benzene (C₆H₆) reacts with gaseous oxygen to form carbon dioxide and liquid water.

Reactants: benzene (C₆H₆) and gaseous oxygen (O₂). Products: carbon dioxide (CO₂, because C has valence IV) and liquid water (H₂O).

The balanced chemical equation is:

C₆H₆(l) + 15/2 O₂(g) → 6CO₂(g) + 3H₂O(l)

In this case, we need a coefficient of 15/2 for O₂ because on the product side there are 15 atoms of O (12 in CO₂ and 3 in H₂O).

6 0
3 years ago
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