Question

Chalcopyrite, the principal ore of copper (Cu), contains 34.63 percent Cu by mass. How many grams of Cu can be obtained from 7.35 x 10^3 kg of the ore?

Answer 1

Answer:

$2.55\times 10^{6}g$ Cu can be obtained from $7.35\times 10^{3}kg$ ore

Explanation:

1 kg = 1000 g

So, mass of ore is $(7.35\times 10^{3}\times 1000)g$ = $7.35\times 10^{6}g$

Now, 100 g of ore contains 34.63 g of Cu

So, $7.35\times 10^{6}g$ ore contains $\frac{(34.63g)\times (7.35\times 10^{6}g)}{100g}$ Cu or $2.55\times 10^{6}g$ Cu.