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pentagon [3]
3 years ago
13

An atom has the following three isotopes: 24 amu (percent abundance = 78.99%)25 amu (percent abundance =10.00\%) , and 26 amu (p

ercent bundance=11.01\%) . Calculate the average atomic mass. What is the identity of this atom based on your calculation?
Chemistry
2 answers:
weeeeeb [17]3 years ago
8 0
We multiply each mass with its percentage.
24*(78.99/100) = 18.96
25*(10/100)= 2.5
26*(11.01/100)= 2.86
Then add these together.
18.96+2.5+2.86= 24.32amu
An element that has an average mass of nearly 24.32amu would be Mg (magnesium)
tamaranim1 [39]3 years ago
8 0
The average atomic mass is 24.31. The element is likely Magnesium.

Work:
24(0.7899) = 18.95
25(0.1000) = 2.5
26(0.1101) = 2.86
18.95 + 2.5 + 2.86 = 24.31
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Solution A: crenation

Solution B: hemolysis

Solution C: hemolysis

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Solution E: crenation

Explanation:

Hemolysis is the rupturing of red blood cells, which results in the release of hemoglobin (from within the red blood cells) into the plasma. If a red blood cell is placed in a hypotonic solution, water will flow into the cell, the cell will swell and hemolysis will.

Crenation: when a red blood cell is placed in a <em>hypertonic solution (</em>such as highly saline solution), the red blood cell will lose water(osmosis) and will shrink in size. The red blood cell has undergone crenation.

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