An atom has the following three isotopes: 24 amu (percent abundance = 78.99%)25 amu (percent abundance =10.00\%) , and 26 amu (p ercent bundance=11.01\%) . Calculate the average atomic mass. What is the identity of this atom based on your calculation?
2 answers:
We multiply each mass with its percentage.
The average atomic mass is 24.31. The element is likely Magnesium.
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Answer:
10.28 mol
Explanation:
S + 2O = SO2
(atm x L) ÷ (0.0821 x K)
(3.45 x 45.6) ÷ (0.0821 x 373)
=5.13726
Then round it to significant figures
=5.14
5.14 mol SO2 x (2 mol O ÷ 1 mol SO2)
=10.28 mol O
<span>Answer:
Moles Ca(NO3)2 = 100 x 0.250 / 1000 = 0.025
Ca(NO3)2 >> Ca2+ + 2NO3-
Moles NO3- = 2 x 0.025 = 0.05
Moles HNO3 = 400 x 0.100 / 1000 = 0.04
Total moles = 0.05 + 0.04 = 0.09
Total volume = 500 ml = 0.500 L
M = 0.09 / 0.500 = 0.18</span>
..........The answer is B
Answer:
H2O
Explanation:
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