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DaniilM [7]
3 years ago
12

What is the answer to this math problem?

Mathematics
1 answer:
ladessa [460]3 years ago
8 0
My answer was d and I've got this question in my math book and that's what I answered
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What is 2+2 (FP)<br> 1. 4<br> 2. 98<br> 3. 19
lesya692 [45]
The answer is 2+2=4
5 0
3 years ago
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How do you graph this equation 1/3x-1/6y=0
Lubov Fominskaja [6]
\frac{1}{3}x- \frac{1}{6}y=0 \\ \\\frac{1}{6}y = \frac{1}{3}x \ \ /*6 \\ \\y=\frac{1}{\not3^1}x*\not6^2 \\ \\y=2x


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3 years ago
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Graph the linear equation. Find three points that solve the equation, then plot on the graph. -3y=x-6
nata0808 [166]

Answer:

Step-by-step explanation:                               x - 6

The given equation can be re-written as y = ---------                              

                                                                             -3

Arbitrarily choose x = 0.  Then:

      x - 6         0-6

y = --------- = ----------- = 2, so (0, 2) is a point on the graph which is also the                              

          -3            -3                                                                  y-intercept

Arbitrarily choose x = 6.  Then y = 0, and (6, 0) is another point on the graph                                    

                                                              which happens to be the x-intercept

arbitrarily choose x = 12.  Then y = (12 - 6) / (-3) = -2.  Then  (12, -2) is            

                                                                                  another point on the

                                                                                  graph.

Plot (12, -2), (6, 0) and (0, 2).  Draw a line through these three points.

6 0
3 years ago
1. Solve for the variable. x - 4.5 = 11.3 ​
polet [3.4K]

Answer:

15.8

Step-by-step explanation:

do 11.3 + 4.5 = 15.8

7 0
3 years ago
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16. Let W be the set of all vectors in R3 of the form a+2b b -3a Find a basis for Wand state the dimension of W.
Yuki888 [10]

Answer:

W=\{\left[\begin{array}{ccc}a+2b\\b\\-3a\end{array}\right]: a,b\in\mathbb{R} \}

Observe that if the vector x=\left[\begin{array}{ccc}x\\y\\z\end{array}\right] is in W then it satisfies:

\left[\begin{array}{ccc}x\\y\\z\end{array}\right]=\left[\begin{array}{c}a+2b\\b\\-3a\end{array}\right]=a\left[\begin{array}{c}1\\0\\-3\end{array}\right]+b\left[\begin{array}{c}2\\1\\0\end{array}\right]

This means that each vector in W can be expressed as a linear combination of the vectors \left[\begin{array}{c}1\\0\\-3\end{array}\right], \left[\begin{array}{c}2\\1\\0\end{array}\right]

Also we can see that those vectors are linear independent. Then the set

\{\left[\begin{array}{c}1\\0\\-3\end{array}\right], \left[\begin{array}{c}2\\1\\0\end{array}\right]\} is a basis for W and the dimension of W is 2.

7 0
3 years ago
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