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Maslowich
3 years ago
10

Round to the nearest ten and hundred 829

Mathematics
2 answers:
Marysya12 [62]3 years ago
6 0
Nearest 10th = 830
Nearest 100th = 800
Musya8 [376]3 years ago
4 0
To the nearest ten, 829 would become <em><u>830</u></em> because the ones digit (9) is closer to 30 than it is to 20. So we would round up.

To round to the nearest hundred, we look at the tens and ones digit. 29 is less than 50 so we would have to round down to <em><u>800</u></em> instead of rounding up to 900.

Hope that helps :)
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well how menny hours per day?

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3 years ago
What is the real number value of m^3+ √12 m when 5m^2 = 45 ?
babymother [125]
<h3>Answer: H. 33</h3>

=============================================

Work Shown:

Solve 5m^2 = 45 for m to get

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--------------

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5 0
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Consider the function and its inverse.
Ber [7]

Answer:

The domain of f(x) is restricted to x\leq 0, and the domain of f^{-1}(x) is restricted to x\geq 4.

Step-by-step explanation:

From Function Theory we know that domain of a function is the set of values such that an image exist. Let f(x) = x^{2}+4 and f^{-1}(x) = \sqrt{x-4} the function and its inverse, respectively.

At first glance we notice that function is a second order polynomial and every polinomial is a continuous function and therefore, there exists an image for every element of domain.

But domain of its inverse is restricted to every value of x so that x-4 \geq 0, which means that x\geq 4.

Finally, we concluded that following answer offers the best approximation to our result:

The domain of f(x) is restricted to x\leq 0, and the domain of f^{-1}(x) is restricted to x\geq 4.

6 0
3 years ago
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