Answer:
where is the equation please put it
We need to correctly choose exactly 4 out of the 6 drawn numbers.
Apply hypergeometric distribution:
a=number of correctly chosen numbers = 4
A=number of correct (drawn) numbers = 6
b=number of incorrectly chosen numbers = 2
B=number of undrawn numbers = 44-6 = 38
Then by the hypergeometric distribution
P(a,b,A,B)
=C(A,a)C(B,b)/C(A+B,a+b) [C(n,r)=combination of r objects taken out of n]
=C(6,4)C(38,2)/C(44,6)
=15*703/7059052
= 10545/7059052
= 0.001494 (to the nearest millionth)
Answer: probability of winning third prize is 10545/7059052=0.001494
Answer:
4.332 x 10 to the 3 power I do believe
Step-by-step explanation:
Answer:
Let pork chops and ground beef be x and y respectively.
4x = $12.60
x = $3.15
11x = $34.65
5y = $10.25
y = $2.05
12y = $24.60
11x + 12y = $34.65 + $24.60
= $59.25
