Y=x +2 and y= -3x y=-x - 2 and 2x-3y = -9 y= 2x -1 and y= x +1 x-2y = -25 and 3x -y = 0
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Let the amount invested with 5% interest be x
Therefore, the amount invested with 6% interest will be (6000-x)
It is given that the total interest earned yearly is $337.5. Thus, the equation of interest will be:
Multiplying both sides by 100 we get:
Subtracting both sides by 36000 we get:
Thus, the amount invested at 5% is $2250
Therefore, the amount invested at 6% will be $(6000-2250)=$3750