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3 years ago

N is m% of what? pls answer asap thx!

Mathematics

1 answer:

beks73 [17]3 years ago

3 0

Answer:

m% = m/100

Step-by-step explanation:

what = a variable ... "x". for example.

"is" means "="

"of" means multiply

n = (m/100)•x

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Two ride-sharing companies are competing for business in a large city. To help customers compare the companies, a data scientist

Solnce55 [7]

Solution :

Given :

$n_1 = n_2 = 40$

$\overline X_1 = 18$

$S_1 = 4$

$\overline X_2 = 12$

$S_2 =10$

So we want to test :

$H_0 : \mu_1=\mu_2$ vs $H_1 : \mu_1 \neq \mu_2$

a). For 98% confidence interval :

$=\left((\overline X_1 - \overline X_2) \pm Tn_1+n_2-2, \alpha / 2 \sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}\right)$

$=\left((18-12) \pm 2.375 \sqrt{\frac{4^2}{40}+\frac{10^2}{40}}\right)$

$=(6 \pm 4.0445)$

= (1.956, 10.045)

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Cbegin%7Bequation%7D%5Ctext%20%7B%20Question%3A%20If%20%7D%20%5Cln%20%28x%2By%29%3D4%20%5Cti

Art [367]

I think you meant to say

$\ln(x+y) = 4xy$

and not "4 times y" on the right side (which would lead to a complex value for y when x = 0). Note that when x = 0, the equation reduces to ln(y) = 0, so that y = 1.

Implicitly differentiating both sides with respect to x, taking y = y(x), and solving for dy/dx gives

$\dfrac{1+\frac{dy}{dx}}{x+y} = 4y + 4x\dfrac{dy}{dx}$

$\implies \dfrac{dy}{dx} = \dfrac{4xy+4y^2-1}{1-4x^2-4xy}$

Note that when x = 0 and y = 1, we have dy/dx = 3.

Differentiate both sides again with respect to x :

$\dfrac{d^2y}{dx^2} = \dfrac{(1-4x^2-4xy)\left(4y+4x\frac{dy}{dx}+8y\frac{dy}{dx}\right)-(4xy+4y^2-1)\left(-8x-4y-4x\frac{dy}{dx}\right)}{(1-4x^2-4xy)^2}$

No need to simplify; just plug in x = 0, y = 1, and dy/dx = 3 to get

$\dfrac{d^2y}{dx^2} \bigg|_{x=0} = \boxed{40}$

8 0

2 years ago

Solve the inequality.<br><br><br> n + 9 < −3

storchak [24]

When solving this inequality, you would do the inverse to the other side.

Subtraction is the inverse of addition.

So,

n + 9 (-9) <-3 (-9)

n<-12

When you subtract two negative numbers, you continue to the left of the number line.

I hope this helps!
~cupcake

7 0

4 years ago

A region R is enclosed by the coordinate axes and the graph of y=k(x-5)^2, k>0. When this region is revolved around the x-axi

r-ruslan [8.4K]

$y=k(x-5)^2$ touches the x-axis at $x=5$ and has a y-intercept when $x=0$ at

$y=k(0-5)^2=25k$

Using disks, the volume of the revolved region would be given by the integral

$\displaystyle\pi\int_0^5\bigg(k(x-5)^2\bigg)^2\,\mathrm dx=\pi k^2\int_0^5(x-5)^4\,\mathrm dx=\pi k^2\int_{-5}^0x^4\,\mathrm dx$
$\implies 2500\pi=625\pi k^2$
$\implies 4=k^2$
$\implies k=2$

6 0

3 years ago

Read 2 more answers

Given that RT ≅ WX, which statement must be true?

Anettt [7]

RT + tw = wx + tw is the right answer

3 0

3 years ago