Answer:
225 m.
Explanation:
Applying the equation of motion.
v² = u²+2as..................... Equation 1
Where v = final velocity of the car, u = initial velocity of the car, a = acceleration of the car, s = distance traveled by the car.
make s the subject if the equation.
s = (v²-u²)/2a.................... Equation 2
Given: v = 0 m/s, u = 30 m/s, a = -2 m/s²
Substitute into equation 2
s = (0²-30²)/(-2×2)
s = -900/-4
s = 225 m.
Hence the maximum distance the car travels up the hill = 225 m.
Complete Question
A loaded tractor-trailer with a total mass of 5000 kg traveling at 3.0 km/h hits a loading dock and comes to a stop in 0.64 s. What is the magnitude of the average force exerted on the truck by the dock
Answer:
The value is 
Explanation:
From the question we are told that
The total mass is 
The time taken to come to a stop is 
The initial velocity is 
Generally the magnitude of the average force exerted on the truck by the dock is mathematically represented as

Here v is the final velocity which is zero since the truck came to a stop

=> 
Answer:
the boat will either break or go alot faster
Explanation:
First you need an idea second you need a plan