Answer:
V = 6 m/s
Explanation:
Given that,
Initial speed of an object is 20 m/s
Final speed of an object is 10 m/s
Time, t = 5 s
We need to find the average speed of the object during these 5 seconds. Let it is equal to V. Here, time is same. The average speed is given by :
So, the average speed of the object is 6 m/s.
Q: The small piston of a hydraulic lift has a cross-sectional of 3.00 cm2 and its large piston has a cross-sectional area of 200 cm2. What downward force of magnitude must be applied to the small piston for the lift to raise a load whose weight is Fg = 15.0 kN?
Answer:
225 N
Explanation:
From Pascal's principle,
F/A = f/a ...................... Equation 1
Where F = Force exerted on the larger piston, f = force applied to the smaller piston, A = cross sectional area of the larger piston, a = cross sectional area of the smaller piston.
Making f the subject of the equation,
f = F(a)/A ..................... Equation 2
Given: F = 15.0 kN = 15000 N, A = 200 cm², a = 3.00 cm².
Substituting into equation 2
f = 15000(3/200)
f = 225 N.
Hence the downward force that must be applied to small piston = 225 N
<span>The factors that are used to determine power are:
Voltage,current and the power factor.
</span><span>Power = Voltage x Current x K
Watts = Volts x Amps x Power Factor</span>
Answer:
Point A
Explanation:
The work done by stretching or compressing a spring is given by E=1/2kx²
The potential energy is numerically equal to the work done.
This means that the higher the bigger the value of the extension, x, the higher the energy contained.
In this scenario the modulus of x is considered.
Among the given values of x the modulus of -5 is the largest.
thus it gives the highest value of energy.
Answer:
C.) 1.5 kg
Explanation:
Start with the equation:
Plug in what you know, and solve:
Find matching soluation:
C.) 1.5 kg
