Answer:
T = 2010 N
Explanation:
m = mass of the uniform beam = 150 kg
Force of gravity acting on the beam at its center is given as
W = mg
W = 150 x 9.8
W = 1470 N
T = Tension force in the wire
θ = angle made by the wire with the horizontal = 47° deg
L = length of the beam
From the figure,
AC = L
BC = L/2
From the figure, using equilibrium of torque about point C
T (AC) Sin47 = W (BC)
T L Sin47 = W (L/2)
T Sin47 = W/2
T Sin47 = 1470
T = 2010 N
Answer:
The magnitude of force per unit length of one wire on the other is
and the direction is away from one another
The magnitude of force per unit length of one wire on the other is
and the direction is towards each other.
Explanation:
= Vacuum permeability = 
= Current in first wire = 2.9 A
= Current in second wire = 5.3 A
r = Gap between the wires = 11 cm
Force per unit length

The magnitude of force per unit length of one wire on the other is
and the direction is away from one another

The magnitude of force per unit length of one wire on the other is
and the direction is towards each other.
Answer:
3.1×10⁻¹¹ N
Explanation:
Use Coulomb's law:
F = k q₁ q₂ / r²
F = (9×10⁹) (6.0×10⁻¹⁰) (2.3×10⁻¹⁵) / (0.02 m)²
F = 3.1×10⁻¹¹