The frequency of the radio station is
For radio waves (which are electromagnetic waves), the relationship between frequency f and wavelength
is
where c is the speed of light. Substituting the frequency of the radio station, we find the wavelength:
Answer:
Capacitance, C = 26.1 picofarad
Explanation:
It is given that,
Side of square, x = 4.3546 cm = 0.043546 m
Distance between electrodes, d = 0.6408 mm = 0.0006408 m
Voltage, V = 73.68 V
Capacitance of parallel plates is given by :
or
C = 26.1 picofarad
So, the capacitance of the capacitor is 26.1 picofarad. Hence, this is the required solution.
Answer:
Explanation:
1. We can find the temperature of each star using the Wien's Law. This law is given by:
![\lambda_{max}=\frac{b}{T}=\frac{2.9x10^{-3}[mK]}{T[K]}](https://tex.z-dn.net/?f=%5Clambda_%7Bmax%7D%3D%5Cfrac%7Bb%7D%7BT%7D%3D%5Cfrac%7B2.9x10%5E%7B-3%7D%5BmK%5D%7D%7BT%5BK%5D%7D)
(1)
So, the temperature of the first and the second star will be:
Now the relation between the absolute luminosity and apparent brightness is given:
(2)
Where:
- L is the absolute luminosity
- l is the apparent brightness
- r is the distance from us in light years
Now, we know that two stars have the same apparent brightness, in other words l₁ = l₂
If we use the equation (2) we have:
So the relative distance between both stars will be:
(3)
The Boltzmann Law says, 
(4)
- σ is the Boltzmann constant
- A is the area
- T is the temperature
- L is the absolute luminosity
Let's put (4) in (3) for each star.
As we know both stars have the same size we can canceled out the areas.
I hope it helps!
Answer:
Tuning the keys.
Explanation:
<em>"Guitar strings are tuned (tightened and loosened) using their tuning keys. </em><em>Applying too much tension to a string tightly can raise it to the pitch of the next note, while loosening it can easily lower it the same amount.</em><em> Increasing the tension raises the pitch. The length of a string is also important."</em>
<em />
I hope this answers your question! Have a good night!
Answer:
Gravitational force will be 16 times more.
Explanation:
we know;
Gravitational force (F) = (Gm1m2)/d^2
when mass of each is doubled and distance between them is halved;
F= (G2m1×2m2)/(d/2)^2
=(4Gm1m2)/(d^2/4)
=4×4(Gm1m2)/d^2
=16(Gm1m2)/d^2
=16F
