Question

One mole of an unknown sample contains 120 g of carbon and 30.3 g of

Answer 1

atomic mass of carbon is C = 12 g/mol

atomic mass of hydrogen is H = 1 g/mol

now number of carbon atoms

$N_c = \frac{120}{12} = 10$

Similarly the number of hydrogen atoms are

$N_H = \frac{30.3}{1} = 30$

so Carbon atom and hydrogen atom must be in ratio of 10:30

so the ratio is 1:3

now the empirical formula is always in simplest form

$CH_3$