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Scorpion4ik [409]
3 years ago
7

#6------I need help...

Mathematics
1 answer:
Lena [83]3 years ago
5 0
F because the other answers are way to high 
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If you know the area of a circular field is 6358.5 m2, what is the radius of the field?
diamong [38]

Answer:

r = 45 m.

Step-by-step explanation:

pi r^2 = 6358.5

r^2 = 6358.5 / pi

r = √(6358.5 / pi)

= 44.989 m

5 0
3 years ago
What is the value of the underline digit 6 6,560
egoroff_w [7]
6,000 because 6 it in the thousands place
8 0
3 years ago
Help plz i need this done
Romashka [77]

Answer:

x ≈ 11.5

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Trigonometry</u>

  • [Right Triangles Only] SOHCAHTOA
  • [Right Triangles Only] sin∅ = opposite over hypotenuse

Step-by-step explanation:

<u>Step 1: Identify Variables</u>

Angle = 35°

Opposite Leg = <em>x</em>

Hypotenuse = 20

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Substitute [sine]:                    sin35° = x/20
  2. Isolate <em>x</em>:                                 20sin35° = x
  3. Evaluate:                                 11.4715 = x
  4. Rewrite:                                  x = 11.4715
  5. Round:                                    x ≈ 11.5
5 0
2 years ago
What is the distance between the points (2, 5) and (5,7)?
Svetlanka [38]

Answer:

\sqrt{13}

Step-by-step explanation:

The distance formula that gives the distance between two points is given as:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Plugging in our given points, we get:

d=\sqrt{(5-2)^2+(7-5)^2},\\d=\sqrt{3^2+2^2},\\d=\sqrt{9+4},\\d=\fbox{$\sqrt{13}$}.

6 0
2 years ago
A scientist needs 10 liters of a 20% acid solution for an experiment, but she has only a 5% solution and a 40% solution. To the
tamaranim1 [39]

Answer:

The volume of 40% solution= 4.3L

The volume of 5% solution= 10L - 4.3L= 5.7L

Step-by-step explanation:

From the given information:

Let consider  x to be the of volume 40% solution

therefore the volume of 5% is said to be:

10 L= 40% solution volume + 5% solution volume

10 L= (x + 5%) solution volume

making 5% solution volume the subject; we have

5% solution volume= 10 L - x

To estimate the value of the volume, we now have:

Volume  of 20% × Concentration of  20%= (Volume of 40%  × concentration40%) + (Volume of 5% × Concentration of 5% )

∴

10L  ×  20%= (x) L × 35% + 10 L × 5%

(x) L × 35 = 10L × 20 - 10 L × 5 = 10 L × 15

x L = 10L \times \dfrac{15}{35}

x = 4.28 L

x \simeq 4.3L

∴

The volume of 40% solution= 4.3L

The volume of 5% solution= 10L - 4.3L= 5.7L

8 0
3 years ago
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