Question

Energy Levels: An ionized atom having Z protons has had all but one of its electrons removed. If E is the total energy of the ground state electron in atomic hydrogen, then what is the total energy of the remaining electron in the ionized atom?

Answer 1

Explanation:

Formula for energy value is as follows.

                     E = $\frac{-E_{0}}{n^{2}}$

where,      $E_{0}$ = 13.6

                         n = number of shell                          

So, at ground state energy  of hydrogen atom will be as follows.

                    E = $\frac{-E_{0}}{n^{2}}$

                       = $\frac{-13.6}{(1)^{2}}$

                      = -13.6

Hence, for an ionized atom value of energy will be as follows.

                    E' = $-13.6 \times Z^{2}$

    or,            E' = $E \times Z^{2}$

Thus, we can conclude that total energy of the remaining electron in the ionized atom is $E \times Z^{2}$.