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frez [133]
3 years ago
5

A functional group of atoms, such as OH, is called a

Chemistry
1 answer:
Licemer1 [7]3 years ago
7 0
<span>Hydroxy group..

... :):) ....</span>
You might be interested in
A 100 g sample of potassium chlorate, KCIO3(s), is completely decomposed by heating:
Mama L [17]
Explanation:
In order to be able to calculate the volume of oxygen gas produced by this reaction, you need to know the conditions for pressure and temperature.
Since no mention of those conditions was made, I'll assume that the reaction takes place at STP, Standard Temperature and Pressure.
STP conditions are defined as a pressure of
100 kPa
and a temperature of
0
∘
C
. Under these conditions for pressure and temperature, one mole of any ideal gas occupies
22.7 L
- this is known as the molar volume of a gas at STP.
So, in order to find the volume of oxygen gas at STP, you need to know how many moles of oxygen are produced by this reaction.
The balanced chemical equation for this decomposition reaction looks like this
2
KClO
3(s]
heat
×
−−−→
2
KCl
(s]
+
3
O
2(g]
↑
⏐
⏐
Notice that you have a
2
:
3
mole ratio between potassium chlorate and oxygen gas.
This tells you that the reaction will always produce
3
2
times more moles of oxygen gas than the number of moles of potassium chlorate that underwent decomposition.
Use potassium chlorate's molar mass to determine how many moles you have in that
231-g
sample
231
g
⋅
1 mole KClO
3
122.55
g
=
1.885 moles KClO
3
Use the aforementioned mole ratio to determine how many moles of oxygen would be produced from this many moles of potassium chlorate
1.885
moles KClO
3
⋅
3
moles O
2
2
moles KClO
3
=
2.8275 moles O
2
So, what volume would this many moles occupy at STP?
2.8275
moles
⋅
22.7 L
1
mol
=
64.2 L
6 0
3 years ago
What are the products obtained in the electrolysis of molten nai?
yanalaym [24]
Answer is: sodium (Na) and iodine (I₂).

<span> First ionic bonds in this salt are separeted because of heat: 
</span>NaI(l) → Na⁺(l) + I⁻(l).

Reaction of reduction at cathode(-): Na⁺(l) + e⁻ → Na(l) /×2.

2Na⁺(l) + 2e⁻ → 2Na(l).

Reaction of oxidation at anode(+): 2I⁻(l) → I₂(l) + 2e⁻.

The anode is positive and the cathode is negative.


4 0
3 years ago
Hydrogen chloride, HCl, is classified as an Arrhenius acid because it produces(1) H+ ions in aqueous solution(2) Cl– ions in aqu
frozen [14]
Answer is (1) Produces H+ in aqueous solution
8 0
3 years ago
How can you make a solution more saturated?
NNADVOKAT [17]
Heat the solution till all the water molecules are no longer in the solution.
Or add more solute till it stops dissolving.(maximum point of dissolvtion.)
7 0
3 years ago
13. Find the total number of atoms present in the following molecules. a. 5 H₂O b. Zn Cl₂
Phantasy [73]

Answer:

5H²O= 23

ZnCl²=135

have a great day

7 0
3 years ago
Read 2 more answers
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