ν = 2.26 * 10¹⁴ Hz
c = 3.0 * 10⁸
Using wave equation
c = λν
λ = c/ν
λ = 3.0 * 10⁸/2.26 * 10¹⁴
λ = 1.3 * 10⁻⁶
Answer:
SF2 > H2O > PBr3 > NCl3
Explanation:
Compare the electronegativity values for the atoms and classify the nature of the bonding based on the electronegativity difference.
P has an electronegativity of 2.1, while Br has an electronegativity of 2.96. The difference is 0.86, indicating that these atoms will form covalent bonds.
S has an electronegativity of 2.58 while F has an electronegativity of 4.0. The difference is 1.42, indicating that these atoms will form polar covalent bonds.
O has an electronegativity of 3.5 while H has an electronegativity of 2.1. The difference is 1.4, indicating that these atoms will form polar covalent bonds.
N has an electronegativity of 3.04, whereas Cl has an electronegativity of 3.5. This difference of 0.46 indicates that these atoms will form covalent bonds.
We know that the greater the electronegativity, the higher the polarity. In decreasing order of polarity, we have:
SF2 > H2O > PBr3 > NCl3
When the forward and reverse reaction rates are occuring at the same rate, the system is at equilibrium
Answer:
(a).
![order \: of \: A = 2 \\ order \: of \:B = 0 \\ rate = k[A] {}^{2} [B]](https://tex.z-dn.net/?f=order%20%5C%3A%20of%20%5C%3A%20A%20%3D%202%20%5C%5C%20order%20%5C%3A%20of%20%5C%3AB%20%20%3D%200%20%5C%5C%20rate%20%3D%20k%5BA%5D%20%7B%7D%5E%7B2%7D%20%5BB%5D)
(b)
(c). The rate increases because kinetic energy of reactant molecules increases.
