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Semenov [28]
3 years ago
15

Kernel structure for manganese

Chemistry
1 answer:
Amanda [17]3 years ago
3 0

Answer:

The nucleus consists of 25 protons (red) and 30 neutrons (blue). 25 electrons (green) bind to the nucleus, successively occupying available electron shells (rings). Manganese is a transition metal in group 7, period 4, and the d-block of the periodic table. It has a melting point of 1246 degrees Celsius.

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a molecule in a chemical reaction that has its chemical bonds broken is called the _______ in the reaction?​
nika2105 [10]

Answer:

reactants

Explanation:

8 0
3 years ago
An irregular lump of an unknown metal has a measured density of 5.50 g/mL. The metal is heated to a temperature of 153 °C and pl
Oliga [24]

Answer: 0.543J/g^0C

Explanation:

Volume of metal = volume of water displaced = (30.0 - 25.0) ml = 5.0 ml

Density of metal = 5.50 g/ml

Mass of metal =density\times volume =5.50\times 5.0=27.5g

Volume of water = 25.0 ml

Density of metal = 1.0 g/ml

Mass of metal =density\times volume =1.0\times 25.0=25.0g

heat_{absorbed}=heat_{released}

As we know that,  

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

-[m_1\times c_1\times (T_{final}-T_1)]=[m_2\times c_2\times (T_{final}-T_2)]         .................(1)

where,

q = heat absorbed or released

m_1 = mass of metal = 27.5 g

m_2 = mass of water = 25.0 g

T_{final} = final temperature = ?41.0^0C

T_1 = temperature of metal = 153^oC

T_2 = temperature of water = 25.0^oC

c_1 = specific heat of lead = ?

c_2 = specific heat of water= 4.184J/g^0C

Now put all the given values in equation (1), we get

27.5g\times c_1\times (41.0-153)^0C=[25.0g\times 4.814J/g^0C\times (41.0-25.0)^0C]

c_1=0.543J/g^0C

Thus the specific heat of the unknown metal sample is 0.543J/g^0C

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3 years ago
Dr. Thomas was doing laundry and accidentally knocked over the entire bottle of liquid laundry detergent (true story!). What wou
neonofarm [45]
Baking soda is the correct
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A colligative property of a solution is one that depends 1. on the identity of the solute and the concentration of the solution.
Tanzania [10]

Answer:

The correct answer is option 2.

Explanation:

Colligative property is defined as property which depends upon only on the numbers of particles of solute dissolved in definite amount of  solvent, It do not depend on the nature of the solute.

For example : NaCl solution with 0.4 molal will show same colligative properties as a that of the glucose solution with 0.04 molal concentration.

The following are the examples of colligative property:

1. Relative lowering of vapor pressure.

2. Osmotic pressure

3. Elevation in boiling points

4. Depression in freezing point

5 0
3 years ago
QUESTION THREE
BartSMP [9]

Answer:

Odds to be given for an event that either Romance or Downhill wins is 11:4

Explanation:

Given an odd, r = a : b. The probability of the odd, r can be determined by;

     Pr(r) = \frac{a}{b} ÷ (

So that;

Odd that Romance will win = 2:3

Pr(R) = \frac{2}{3} ÷ (

        = \frac{2}{3} ÷ \frac{5}{3}

       = \frac{2}{5}

Odd that Downhill will win = 1:2

Pr(D) = \frac{1}{2} ÷ (

        =  \frac{1}{2} ÷ \frac{3}{2}

        = \frac{1}{3}

The probability that either Romance or Downhill will win is;

Pr(R) + Pr(D) = \frac{2}{5} +  \frac{1}{3}

                    = \frac{11}{15}

The probability that neither Romance nor Downhill will win is;

Pr(neither R nor D) = (1 - \frac{11}{15})

                               = \frac{4}{15}

The odds to be given for an event that either Romance or Downhill wins can be determined by;

                               = Pr(Pr(R) + Pr(D)) ÷ Pr(neither R nor D)

                               = \frac{11}{15} ÷ \frac{4}{15}

                              = \frac{11}{4}

Therefore, odds to be given for an event that either Romance or Downhill wins is 11:4

8 0
3 years ago
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