Given: <PQR is a right angle Prove: <PQS and <SQR are complemantary
1 answer:
Answer:
see the explanation
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
m∠PQS+m∠SQR=m∠PQR ----> equation A (by Addition Angle Postulate)
we have that
m∠PQR=90° ----> equation B given problem (because is a right angle)
substitute equation B in equation A
m∠PQS+m∠SQR=90°
Remember that
Two angles re complementary is their sum is equal to 90 degrees (Definition of complementary angles)
therefore
m∠PQS and m∠SQR are complementary angles
You might be interested in
Answer:
A'(0,-1), B'(1,0) , C'(3,-2), and D'(2,-3)
Step-by-step explanation:
The coordinates of rectangle ABCD are A(-1,0), B(0,-1), C(-2,-3), (-3,-2).
The mapping for a rotation through 90° clockwise about the origin is
Therefore:
Therefore the image rectangle has coordinates:
A'(0,-1), B'(1,0) , C'(3,-2), and D'(2,-3)
The first choice is correct.