Answer:
0.20kg-m^2
Explanation:
Let the linear velocity of the rope(=of pulley) is v m/s
Using kinematic equation
=> v = u + at
=>v = 0 + 4.9a
=>v = 4.9a ------------ eq1
By v^2 = u^2 + 2as
=>v^2 = 0 + 2 x v/4.9 x 1.2
=>4.9v^2 - 2.4v = 0
=>v(4.9v - 2.4) = 0
=>v = 2.4/4.9 = 0.49 m/s
Thus by v = r x omega
=>omega = v/r = 0.49/0.02 = 24.49 rad/sec
BY W = F x s = 50 x 1.2 = 60 J
=>KE(rotational) = W = 1/2 x I x omega^2
=>60 = 1/2 x I x (24.49)^2
=>I = 0.20 kg-m^2
The Hooke's law is a principal of physics that states that the force needed to extend or compress a spring by some distance x scales linearly with respect to that distance.
<span>A body has translatory motion if it moves along a: mcqs </span>
<h2>Greetings!</h2>
To find this value, you need to remember the speed formula:
3 = 6 / 2
Speed = distance ÷ time
Rearrange to make distance the subject:
Distance = speed * time
Simply plug these values into this:
5.6 * 8.25 = 46.2
<h3>So the player will travel 46.2 metres!</h3>
<h2>Hope this helps!</h2>
